Answer:
Because the disturbances are in opposite directions for this superposition, the resulting amplitude is zero for pure destructive interference
Explanation:
Answer:
n = 4 x 10¹⁸ photons
Explanation:
First, we will calculate the energy of one photon in the radiation:

where,
E = Energy of one photon = ?
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m
Therefore,

E = 3.505 x 10⁻¹⁹ J
Now, the number of photons to make up the total energy can be calculated as follows:

<u>n = 4 x 10¹⁸ photons</u>
Assuming that reaching a height 0 doesn’t stop the ball, and that it accelerates at 9.8 m/s^2, the ball would be traveling at 0.5 + 0.7*9.8 = 7.36 m/s downwards.
Through is the answer to your question
Answer:
a' =4.15 m/s²
Explanation:
Given that
m= 3.2 kg
F₁ = 1.9 i −1.9 j N
F₂=3.8 i −10.1 j N
From second law of Newton's
F(net) = m a
F₁ + F₂ = m x a
1.9 i −1.9 j + 3.8 i −10.1 j = 3.2 a
a = 1.78 i - 3.75 j m/s²
The resultant acceleration a'

a' =4.15 m/s²