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diamong [38]
2 years ago
11

Using the equation for decay, calculate the amount left of a radioactive sample amount N0 if the decay constant is 0.00125 secon

ds and the time is 180 seconds? (Hint: Your answer will not be a number. Instead, it will be a decimal or percent of the variable N0
Physics
1 answer:
makkiz [27]2 years ago
5 0

The amount left of a radioactive sample amount N0 if the decay constant is 0.00125 seconds and the time is 180 seconds is 0.7999 N.

<h3>What is half-life?</h3>

The time it takes for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life T1/2 and the decay constant is given by T1/2 = 0.693/λ.

  1. N=N0e−λt
  2. given λ = 0.00125 seconds
  3. t = 180 seconds
  4. Now putting values.
  5. N=N0e−λt = 0.799
  6. N= 0.7999.

Read more about the radioactive :

brainly.com/question/2320811

#SPJ1

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Answer:

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Explanation:

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7 0
3 years ago
A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.0 cm wide and 5.00 m long. Between the sheets is a mica
Evgen [1.6K]

This question is incomplete, the complete question is;

A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.0 cm wide and 5.00 m long. Between the sheets is a mica strip of the same width and length that is 0.0225 mm thick. What is the maximum charge?

(The dielectric constant of mica is 5.4, and its dielectric strength is 1.00×10⁸ V/m)

Answer: the maximum charge q is 716.85 μF

Explanation:

Given data;

with = 3.0 cm = 0.03

breathe = 5.0 m

Area = 0.03 × 5 = 0.15 m²

dielectric strength E = 1.00 × 10⁸

∈₀ = 8.85 × 10⁻¹²

constant K = 5.4

maximum charge = ?

the capacitor C = KA∈₀ / d

q = cv so c = q/v

now

q/v = KA∈₀ / d

q =  vKA∈₀/d = EKA∈₀

we substitute

q = (1.00 × 10⁸) × 5.4 × 0.15 ×  8.85 × 10⁻¹²    

q = 716.85 × 10⁻⁶ F

q = 716.85 μF

the maximum charge q is 716.85 μF

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The force of attraction that a -40.0 μC point charge exerts on a +108 μC point charge has magnitude 4.00 N. How far apart are th
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Answer:

F = k q1 q2 / r^2

r^2 = k q1 q2 / F  = 9E9 * 4E-5 * 10.8E-5 / 4

r^2 = 9 * 4 * 10.8 / 4 * E-1 = 9.72 m^2

r = 3.12 m

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3 years ago
A boat moves at 10.8 m/s relative to the water. If the boat is in a river where the current is 2.00 m/s, how long does it take t
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Answer:

Option E is the correct answer.

Explanation:

Velocity of boat = 10.8 m/s

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Relative velocity upstream = 10.8 - 2 = 8.8 m/s

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        Time in upstream, t₁ = 125 s  

Relative velocity downstream = 10.8 + 2 = 12.8 m/s

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            1100 = 12.8 x t₂

        Time in downstream, t₂ = 86 s  

Total time = t₁ + t₂ = 125 + 86 = 211 s

Option E is the correct answer.           

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What is an example of density
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Ice floating on water and Ice floats on water because it is less dense than water. Things that are less dense float on top of things that are more dense because molecules in ice are further apart than molecules in water.
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