- Show that the equation d=vt2 dimensionally correct or not? ... nalsn7 is waiting for your help. Add your answer and earn points.
The formula for work is

. Plugging in the numbers, you get:


The answer is 30 N.
Answer : The correct option is, (A) 
Solution : Given,
Volume of mercury at temperature
= 
As we know that the mercury is a liquid substance. So, we have to apply the volume of expansion of the liquid.
Formula used for the volume expansion of liquid :
![V_{T}=v_{1}[1+\gamma (T_{2}-T_{1})]](https://tex.z-dn.net/?f=V_%7BT%7D%3Dv_%7B1%7D%5B1%2B%5Cgamma%20%28T_%7B2%7D-T_%7B1%7D%29%5D)
or,
![V_{2}=V_{1}[1+\gamma (T_{2}-T_{1})]](https://tex.z-dn.net/?f=V_%7B2%7D%3DV_%7B1%7D%5B1%2B%5Cgamma%20%28T_%7B2%7D-T_%7B1%7D%29%5D)
where,
= volume of liquid at temperature 
= volume of liquid at temperature 
= volume of liquid at temperature 
= volume expansion coefficient of mercury at
is 0.00018 per centigrade (Standard value)
Now put all the given values in the above formula, we get the volume of mercury at
.
![V_{2}=0.002[1+0.00018(50-20)]=0.0020108m^3](https://tex.z-dn.net/?f=V_%7B2%7D%3D0.002%5B1%2B0.00018%2850-20%29%5D%3D0.0020108m%5E3)
Therefore, the volume of mercury at
is, 
Before she gets into a tuck position, distribution of mass of her body about axis of rotation increases. As a result, her angular velocity decreases. When a diver gets into a tuck position, distribution of mass of her body about axis of rotation becomes less. As a result, her angular velocity increases. During this whole time, there is only one force acting on her body which is her own weight "mg". The net torque acting on her all the time is zero because "mg" force passes through this axis of rotation which causes no moment. Since there is no torque acting on her body, angular momentum should remain constant ( before tuck and after tuck)
Angular momentum is defined as,
L = Iω
Since net torque is zero,
Li = Lf ........... (Li = initial angular momentum, Lf = final angular momentum)
(Iω)i= (Iω)f
Ii = 2.0 kg · m² , ωi = 5.5 rad/s, ωf = <span>11.5 rad/s.
From given, find If. </span>