Answer:
work done = 48.88 ×
J
Explanation:
given data
mass = 100 kN
velocity = 310 m/s
time = 30 min = 1800 s
drag force = 12 kN
descends = 2200 m
to find out
work done by the shuttle engine
solution
we know that work done here is
work done = accelerating work - drag work - descending work
put here all value
work done = ( mass ×velocity ×time - force ×velocity ×time - mass ×descends ) 10³ J
work done = ( 100 × 310 × 1800 - 12×310 ×1800 - 100 × 2200 ) 10³ J
work done = 48.88 ×
J
Answer:
White lane lines separate lanes of traffic moving in the same direction. (UK)
Answer:
the third statement is true
Explanation:
given data
Lenovos cost more than Dells
Lenovos cost less than Apples
solution
we have given 1st statement that is express as
cost (Lenovo) > cost (Dell) ..................1
and
2nd statement that is express as
cost (Lenovo) < cost (Apple)
so we can say it as
cost (Apple) > cost (Lenovo) ......................2
and
now above Both equation 1 and 2 can be written as
cost (Apple) > cost (Lenovo) > cost (Dell) .........................3
so we can say cost of Apples is more than the cost of Lenovos and the cost of Dells
so as that given 3rd statement is true
Answer:
The percentage ductility is 35.5%.
Explanation:
Ductility is the ability of being deform under applied load. Ductility can measure by percentage elongation and percentage reduction in area. Here, percentage reduction in area method is taken to measure the ductility.
Step1
Given:
Diameter of shaft is 10.2 mm.
Final area of the shaft is 52.7 mm².
Calculation:
Step2
Initial area is calculated as follows:


A = 81.713 mm².
Step3
Percentage ductility is calculated as follows:


D = 35.5%.
Thus, the percentage ductility is 35.5%.
Answer:
(a) the velocity ratio of the machine (V.R) = 1
(b) The mechanical advantage of the machine (M.A) = 0.833
(c) The efficiency of the machine (E) = 83.3 %
Explanation:
Given;
load lifted by the pulley, L = 400 N
effort applied in lifting the, E = 480 N
distance moved by the effort, d = 5 m
(a) the velocity ratio of the machine (V.R);
since the effort applied moved downwards through a distance of d, the load will also move upwards through an equal distance 'd'.
V.R = distance moved by effort / distance moved by the load
V.R = 5/5 = 1
(b) The mechanical advantage of the machine (M.A);
M.A = L/E
M.A = 400 / 480
M.A = 0.833
(c) The efficiency of the machine (E);
