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umka2103 [35]
3 years ago
9

In the semi arid regions of China, the country's inhabitants have practiced water harvesting for generations. Water harvesting i

s the process of collecting rainfall and/or runoff for later use. How does this water conservation method help the environment?
A) Water harvesting causes drought-like conditions the rest of the year.
B) Harvesting water during the rainy season has damaged the ecosystem by killing some of the organisms.
C) By collecting run off during the rainy season for future irrigation increases the agricultural production.
D) Run off is one of the main sources of drinking water so there is a shortage of drinking water the remaining part of the year.
Eliminate
Physics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:

its d. By collecting runoff during the rainy season much of the land degredation caused by water erosion is prevented.

Explanation:

lapo4ka [179]3 years ago
3 0

Answer: C) By collecting run off during the rainy season for future irrigation increases the agricultural production

Explanation:

Water harvesting is a process of collection of rain water by using special water storing systems. This water storage practice helps during the scarcity of water like in dry summer seasons and in conditions of drought. Such water can be treated with filters to make it potable for drinking. But generally the water is used for the purpose of irrigation in the agricultural field and household sanitary requirements.

On the basis of the above description, By collecting run off during the rainy season for future irrigation increases the agricultural production is the correct option.

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Look at the graph. What is the slope of the line?
NeTakaya

For the first hour, the slope is zero.

After that, the slope is -2 miles per hour.

7 0
2 years ago
How is the frequency of an electromagnetic wave related to energy
aivan3 [116]

Answer: The energy carried by an electromagnetic wave is proportional to the frequency of the wave.  

Explanation:

Electromagnetic waves that are of higher energy than visible light (higher frequency, shorter wavelength) include ultraviolet light, X-rays, and gamma rays.

7 0
3 years ago
A 2-kg box is pushed to the right by a force of 4 N for a distance of 32 m. It has an initial velocity of 4 m/s to the right. NO
rewona [7]

Answer: a) 8 Kg m/s b) 16 Kg m/s c) 24 Kg m/s d) 16 J e) 128 J f) 144 J

              g) 4 s

Explanation:

a) As momentum by definition is the product of mass times the velocity (is a vector quantity), we can write in this case the following:

pi = m. v₀ = 2 Kg . 4 m/s = 8 Kg. m/s

b) In order to get the change in momentum, we need to get first the final speed of the object.

As we have the total distance travelled, and we could find the acceleration, we could use a kinematic equation to solve the question, but later we will need the kinetic energy, it would be better to apply the work-energy theorem, and calculate ΔK as the work done by external force F, as follows:

ΔK = F . d = 1/2 m (vf² - v₀²)

As we know F, d, m, and v₀, we can solve the equation above for vf:

vf = 12 m/s

So, we can compute the final momentum as follows:

pf = m. vf = 2 Kg. 12 m/s = 24 Kg. m/s

Finally, we can find the change in momentum, as the difference between the final momentum and the initial one, calculated in a):

Δp = pf - pi = 24 Kg. m/s - 8 Kg. m/s = 16 Kg. m/s

c) As we have already found, final momentum is as follows:

pf = m . vf = 2 Kg. 12 m/s = 24 Kg. m/s

d) By definition the initial kinetic energy of the box is as follows:

Ki = 1/2 m v₀² = 1/2. 2 Kg .4² m²/s² = 16 J

e) We can find the change in the kinetic energy taking directly the difference between the final and initial ones, as follows:

ΔK = Kf - Ki = 1/2. 2 Kg (12² - 4²) m²/s² = 128 J

f) From above, we have Kf = 1/2 m. vf² = 1/2 . 2 Kg. 12² m²/s² = 144 J

g) As we know the magnitude of F, and the value of m, we can find the acceleration (assumed constant) , applying Newton's Second Law, as follows:

Fext = m .a ⇒ a = F/m = 4 N / 2 Kg = 2 m/s²

Appying the definition of acceleration, we can solve for t, as follows:

t = (vf-v₀) / a = (12 m/s - 4 m/s) / 2 m/s² = 4 s

6 0
3 years ago
The water stream strikes the inclined surface of the cart. Determine the power produced by the stream if, due to rolling frictio
levacccp [35]

Answer

given,

constant speed of cart on right side = 2 m/s

diameter of nozzle = 50 mm = 0.05 m

discharge flow through nozzle = 0.04 m³

One-fourth of the discharge flows down the incline

three-fourths flows up the incline

Power = ?

Normal force i.e. Fn acting on the cart

F_n = \rho A (v - u)^2 sin \theta

v is the velocity of jet

Q = A V

v = \dfrac{0.04}{\dfrac{\pi}{4}d^2}

v= \dfrac{0.04}{\dfrac{\pi}{4}\times 0.05^2}

v = 20.37 m/s

u be the speed of cart assuming it to be u = 2 m/s

angle angle of inclination be 60°

now,

F_n = 1000 \times \dfrac{\pi}{4}\times 0.05^2\times (20.37 - 2)^2 sin 60^0

F n = 2295 N

now force along x direction

F_x = F_n sin 60^0

F_x = 2295 \times sin 60^0

F_x = 1987.52\ N

Power of the cart

P = F x v

P = 1987.52 x 20.37

P = 40485 watt

P = 40.5 kW

3 0
3 years ago
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion:
lutik1710 [3]

Answer:

  • At t = 1\; \rm s, the particle should have a velocity of -8\; \rm m \cdot s^{-1}.
  • At t = 2\; \rm s, the particle should have a velocity of -1\; \rm m \cdot s^{-1}.
  • At t = 3\; \rm s, the particle should have a velocity of \displaystyle -\frac{8}{27}\; \rm m \cdot s^{-1}.

For a > 0, at t = a \; \text{second}, the particle should have a velocity of \displaystyle -\frac{8}{a^3}\; \rm m \cdot s^{-1}.

Explanation:

Differentiate the displacement of an object (with respect to time) to find the object's velocity.

Note that the in this question, the expression for displacement is undefined (and not differentiable) when t is equal to zero. For t > 0:

\begin{aligned}v &= \frac{\rm d}{{\rm d}t}\, [s] = \frac{\rm d}{{\rm d}t}\, \left[\frac{4}{t^2}\right] \\ &= \frac{\rm d}{{\rm d}t}\, \left[4\, t^{-2}\right] = 4\, \left((-2)\, t^{-3}\right) = -8\, t^{-3} =-\frac{8}{t^3}\end{aligned}.

This expression can then be evaluated at t = 1, t = 2, and t = 3 to obtain the required results.

6 0
3 years ago
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