Answer:
8.049 MW
Explanation:
The expression for gravitational potential energy is given as
Ep = mgh............. Equation 1
Ep = gravitational potential energy, m = mass of water, h = height, g = acceleration due to gravity.
Given: m = 58.4×10³ kg, h = 20.1 m, g = 9.81 m/s²
Substitute into equation 1
Ep = 58.4×10³(20.1)(9.81)
Ep = 1.6098×10⁷ J.
If one half the gravitational potential energy of the water were converted to electrical energy
Electrical energy = Ep/2
Electrical energy = (1.6098×10⁷)/2
Electrical energy = 8.049×10⁶ J
In one seconds,
The power generated = 8.049×10⁶ W
Power generated = 8.049 MW
Answer:
Answer:B
Explanation:
Because it all stayed consistant
Density is given by:
D = M/V
D = density, M = mass, V = volume
Given values:
M = 3.7g, V = 4.6cm³
Plug in and solve for D:
D = 3.7/4.6
D = 0.80g/cm³
Answer:
38 cm from q1(right)
Explanation:
Given, q1 = 3q2 , r = 60cm = 0.6 m
Let that point be situated at a distance of 'x' m from q1.
Electric field must be same from both sides to be in equilibrium(where EF is 0).
=> k q1/x² = k q2/(0.6 - x)²
=> q1(0.6 - x)² = q2(x)²
=> 3q2(0.6 - x)² = q2(x)²
=> 3(0.6 - x)² = x²
=> √3(0.6 - x) = ± x
=> 0.6√3 = x(1 + √3)
=> 1.03/2.73 = x
≈ 0.38 m = 38 cm = x
