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igomit [66]
3 years ago
9

Calculate the entropy change when a. two moles of H2O(g) are cooled irreversibly at constant p from 120°C to 100°C. b. one mole

of H2O(g) is expanded at constant pressure of 2 bar from an original volume of 20 L to a final volume of 25 L. You can consider the gas to be ideal. c. one hundred grams of H2O(s) at -10°C and 1 bar are heated to H2O(l) at +10°C and 1 bar.

Chemistry
1 answer:
alexira [117]3 years ago
3 0

Answer:

The problem solution is given in the attachments.

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Lewis structure for carbon tetrabromide (CBrÁ), in which a central carbon atom is bound to four atoms of the group 7A element br
nlexa [21]
Remember that carbon has 4 electrons in its valence shell meanwhile bromine has 7

So i think the lewis structure would be :

Br

C       Br      Br  

Br

Hope this helps

7 0
3 years ago
6. A 25.0-mL sample of potassium chloride solution was found to have a mass of 25.225 g.
Morgarella [4.7K]

Answer:

6. a. 5.53 (m/m) %; b. 0.7490M

7. 0.156M

Explanation:

6. In the solution of KCl, there are 1.396g of KCl in 25.225g of solution. As mass/mass percent is:

Mass solute / Mass solution * 100

The mass/mass percent of KCl is:

a. 1.396g KCl / 25.225g solution * 100

5.53 (m/m) %

b. Molarity is moles of solute per liters of solution:

<em>Moles KCl -Molar mass: 74.55g/mol-:</em>

1.396g KCl * (1mol / 74.55g) = 0.018726 moles KCl

<em>Volume in liters: 25mL = 0.025L</em>

Molarity:

0.018726 moles KCl / 0.025L = 0.7490M

7. 0.90% means 0.90g of NaCl in 100g of solution:

<em>Moles NaCl -Molar mass: 58.44g/mol-:</em>

0.90g NaCl * (1mol / 58.44g) = 0.0154 moles NaCl

<em>Volume in Liters:</em>

100g * (1mL / 1.01g) = 99mL = 0.099L

Molarity:

0.0154 moles NaCl / 0.099L =

0.156M

4 0
2 years ago
What is the mass of 3.75 moles of NaCI? ( Na= 22.99g/mol, CI= 35.45 g/mol)
seraphim [82]

Answer:

219.15 grams

Explanation:

What is the mass of 3.75 moles of NaCI? ( Na= 22.99g/mol, CI= 35.45 g/mol)

Mole of Na = 22.99g

Mole of Cl = 35.45g

For NaCl we have ratio of 1:1, so we have 1 Na for every Cl

So we just add the two together to get the molar mass of NaCl which is

22.99 + 35.45 = 58.44g/mol

And we know we have 3.75 moles of NaCl so we multiply that by the molar mass of NaCl to get our answer

3.75 x 58.44 = 219.15grams

6 0
3 years ago
Which number should be placed before H20 on the products side of the equation to
timama [110]
<h2>The required balanced equation:</h2><h2>C_3H_8 +5O_2 = 3CO_2 + 4H_2O</h2>

Explanation:

•  Propane when reacts with oxygen it gives carbon dioxide and water.

  • In order to make the equation balanced at both ends of the equation,  

Add 4 as a coefficient before on L.H.S (Left Hand Side) of Equation.

• Therefore, the required balanced equation is:

Propane, when added with 5 molecules of Water, yields 3 molecules of Carbon Dioxide and 4 molecules of water, as shown in the below equation -

C_3H_8 +5O_2 = 3CO_2 + 4H_2O

8 0
2 years ago
How much water would I need to add to 700 mL of a 2.7 M KCl solution to make a 1.0 M solution?
geniusboy [140]

Answer:

1190\ \text{mL}

Explanation:

M_1 = Initial Concentration of KCl = 2.7 M

V_1 = Volume of KCl = 1 M

M_2 = Final concentration of KCl = 1 M

V_2 = Amount of water

We have the relation

M_1V_1=M_2V_2\\\Rightarrow V_2=\dfrac{M_1V_1}{M_2}\\\Rightarrow V_2=\dfrac{2.7\times 700}{1}\\\Rightarrow V_2=1890\ \text{mL}

The amount of water that is to be added is 1890-700=1190\ \text{mL}.

3 0
2 years ago
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