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Andrej [43]
4 years ago
9

Which of the following does not change when a car keeps a constant speed but changes direction?

Chemistry
2 answers:
mestny [16]4 years ago
8 0
An object which experiences either a change in the magnitude or the direction of the velocity vector can be said to be accelerating. This explains why an object moving in a circle at constant speed can be said to accelerate - the direction of the velocity changes.
REY [17]4 years ago
8 0

Answer:

This question is incomplete but the complete question is below

  • Which of the following does not change when a car keeps a constant speed, but changes direction?

a.Acceleration

b.Velocity

c.Momentum

d.Mass

The correct option is d

Explanation:

This question seeks to test the knowledge of the two types of quantity we have in physics; scaler and vector quantities.

A scaler quantity is a quantity that has a magnitude (or numerical value) but no direction while a vector quantity is a quantity that has both magnitude and direction.

The question is obviously asking after a scaler quantity because a value that does not change when affected by direction as stated earlier is a scaler quantity. Acceleration, velocity and momentum are all vector quantities as they are affected by both magnitude and direction but mass remains constant irrespective of direction. Hence, the answer is option d (mass).

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ikadub [295]

Answer: Are there options? I think the answer is continents, but I don't really understand the question. Is continents an option?

Explanation:

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3 years ago
For an amino acid such as aspartic acid, what impact would you expect a neighboring carboxylic acid to have on the apparent pKa
tekilochka [14]

Answer:

The apparent pKa value for aspartic acid increases

Explanation:

The apparent pKa value for aspartic acid increases.  Due to the presence of one negative in close proximity to another negative charge, it causes charge-to-charge repulsion which in turn leads to the increase in pKa values.

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3 years ago
Where does the peak intensity need to fall on the spectrum for a very intense star?
viva [34]

Answer:

Gamma range

Explanation:

A very intense start is a bright star at very high temperature. Now, hotter the object shorter is the wavelength of peak radiation. The increasing order of wavelength of the given regions in the electromagnetic spectrum are:

gamma range < ultra violet < visible < infrared

Ideally, since the shortest wavelength based on the given options is the gamma range, the peak intensity can also be expected to fall at that wavelength. If the star spectrum was recorded in the UV-visible range of the EM spectrum, then it would fall in the UV range

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3 years ago
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3 years ago
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a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the
butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}

Given ,  

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7  ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (21.7 + 273.15) K = 294.85 K  

T₂ = (28.1 + 273.15) K = 301.25 K  

Using above equation as:

\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}

\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K  }}{0.998\ atm}

n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0
3 years ago
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