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prohojiy [21]
3 years ago
15

A solution that contains many dissolved molecules in a fixed amount of solution is called

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer:

  • <em>A solution that contains many dissolved molecules in a fixed amount of solution is called</em> <u>concentrated</u>.

Explanation:

Solutions are homogeneous mixtures.

A solution contains at least one solute component and one solvent component all in the same phase.

The term solubility is used to express the maximum amount of solute that can be dissolved in certain amount of solvent, and is measured at a given temperature and pressure.

You may refer to a solution as <em>concentrated</em> or diluted. These are kind of vague terms, in the sense that they do not express how much solute is dissolved. They just tell if there are many dissolved particles (molecules or ions), which is expressed as concentrated, or just a few particle, which is express as diluted.

Other more specific terms used to refer the amount of solute dissolved in a solution are: unsaturated solution, saturated solution, and supersaturated solution.

<u>Unsaturated solution</u>: the solution contains less solute than what it can have. The solution may dissolve more solute.

<u>Saturated solution</u>: the solution has the maximum amount of solute that it can dissolve, at certain temperature and pressure. If you add more solute to a saturated solution, it will not get dissolved (unless you change the temperature or pressure).

<u>Supersaturated solution</u>: a special condition where the solution contains more solute than the saturated solution, at the same temperature and pressure. This is a very unstable situation and any perturbation will make that the excess solute precipitate.

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Water is 11% hydrogen and 89% oxygen by mass. How many grams of oxygen are in a 250 g glass of water?
mylen [45]

Answer:

mass O2 = 222.5 g

Explanation:

  • %wt = ((mass compound)/(mass sln))×100

balance reaction:

  • 2H2 + O2 ↔ 2H2O

∴ %wt H2 = 11 % = ((mass H2)/(mass H2O))×100

∴ %wt O2 = 89 % = ((mass O2)/(mass H2O))×100

∴ mass H2O 250 g

⇒ mass O2 = (0.89)(250 g)

⇒ mass O2 = 222.5 g

3 0
4 years ago
Calculate the mass (in grams) of calcium carbonate present in a 50.00 mL sample of an aqueous calcium carbonate standard, assumi
horrorfan [7]
1 part per million is the same as 

<span>1 mcg/mL (mcg = 1 micro gram = 1 * 10^-6 grams). </span>
<span>125 ppm = 125 mcg/mL </span>

<span>125 mcg/ml * [1 gram / 1 * 10^6 mgrm] = 1.25 * 10^-4 grams </span>

<span>The density of hard water is 1.000 grams / mL </span>

<span>50 mL of water contains 1.25 * 10^-4 grams. </span>

<span>given mass = 1.25 * 10^-4 </span>
<span>Molar mass = 100.0 grams / mole </span>
<span>n = ????? </span>

<span>n = 1.25 * 10^-4/100 = 1.25 * 10^-6 moles. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

</span>
7 0
3 years ago
a 0.555 g sample of mayonnase was burned in excess oxygen inside a bomb calorimeter with a total heat capacity (bomb and water)
Fofino [41]

Answer:

Dietary\ Calories=65.6kcal

Explanation:

Hello!

In this case, since we can see that the heat released by the combustion of the mayonnaise is absorbed by the bomb calorimeter and water, we can set up the following equation:

m_{mayonnaise}q_{mayonnaise}=C\Delta T

Whereas q for mayonnaise stands for the heat due to its usage; thus, we plug in to obtain:

q_{mayonnaise}=\frac{5.20kJ/\°C*2.93\°C}{0.555g} \\\\q_{mayonnaise}=27.45\frac{kJ}{g}

Now, if 10.0 g are eaten, the energy provided by it turns out:

E_{mayonnaise}=27.45kJ/g*10.0g\\\\E_{mayonnaise}=274.5kJ

And we need that value in dietary calories, 1 kcal:

Dietary\ Calories=274.52kJ*\frac{1kcal}{4.184kJ}\\\\ Dietary\ Calories=65.6kcal

Best regards!

4 0
3 years ago
Which one of the following statements is correct.
k0ka [10]
B. electrons have a negative electrical charge 
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3 years ago
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Which statement is correct concerning the subatomic particles found in an atom?
Mnenie [13.5K]

Answer:

It is D!! Just did this.

Explanation:

Hope this helps :)

3 0
3 years ago
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