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prohojiy [21]
3 years ago
15

A solution that contains many dissolved molecules in a fixed amount of solution is called

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer:

  • <em>A solution that contains many dissolved molecules in a fixed amount of solution is called</em> <u>concentrated</u>.

Explanation:

Solutions are homogeneous mixtures.

A solution contains at least one solute component and one solvent component all in the same phase.

The term solubility is used to express the maximum amount of solute that can be dissolved in certain amount of solvent, and is measured at a given temperature and pressure.

You may refer to a solution as <em>concentrated</em> or diluted. These are kind of vague terms, in the sense that they do not express how much solute is dissolved. They just tell if there are many dissolved particles (molecules or ions), which is expressed as concentrated, or just a few particle, which is express as diluted.

Other more specific terms used to refer the amount of solute dissolved in a solution are: unsaturated solution, saturated solution, and supersaturated solution.

<u>Unsaturated solution</u>: the solution contains less solute than what it can have. The solution may dissolve more solute.

<u>Saturated solution</u>: the solution has the maximum amount of solute that it can dissolve, at certain temperature and pressure. If you add more solute to a saturated solution, it will not get dissolved (unless you change the temperature or pressure).

<u>Supersaturated solution</u>: a special condition where the solution contains more solute than the saturated solution, at the same temperature and pressure. This is a very unstable situation and any perturbation will make that the excess solute precipitate.

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Phosphorus-32 has a half-life of 14.3 days. how many grams of phosphorus-32 remain after 71.5 days if you start with 4.00 grams?
almond37 [142]
Answer : 0.125 g

Explanation : If you are calculating the half life of P-32 which has half life of 14.3 days and you want to calculate how many grams are remaining after 71.3 days if yo are starting with 4 g?

starting you can calculate the number of half life P-32 undergoes first,

which is  n = 71.5 / 14.3 = 5 days.

now, to calculate the remaining mass,

m_{remaining}  = (\frac{initial mass}{2 X 2X 2X2 X2 } ) = (\frac{initial mass}{ 2^{5} } )

= = \frac{4 g }{ 2^{5} } = 0.125 g
7 0
3 years ago
Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.
weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0
3 years ago
Give the name of the element that is a member of the alkali metal family whose most stable ion contains 2 electrons.
notka56 [123]
Lithium

Li → Li⁺ + e⁻

Li 1s²2s¹ → Li⁺ 1s² + e⁻
3 0
4 years ago
100 Points!!!!!!!!
Nikitich [7]

your answer is Particles collide in gas so Substance X is a gas.


6 0
3 years ago
Read 2 more answers
A gas has a temperature of 12 C and a volume of 3.5 L if the temperature is raised to 29C in the pressure is not altered what is
Nataly_w [17]
The answer is V2=3.71
8 0
4 years ago
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