Answer:
1) F = 24 N
2) Distance = 1 m
Explanation:
We are given;
Mass; m = 120 g = 0.12 kg
Initial velocity; u = 20 m/s
Final velocity; v = 0 m/s since it came to rest.
Time; t = 0.1 s
We can calculate acceleration from Newton's first equation of motion;
a = (v - u)/t
a = (0 - 20)/0.1
a = -200 m/s²
1) magnitude of the resistance will be;
F = ma
F = 0.12 × (-200)
F = -24 N
Since, we are dealing with the magnitude, we will take the absolute value. Thus, F = 24 N
2) To find the distance moved by the bullet, we know that;
Distance = Average speed × time
Thus;
Distance = ((v + u)/2) × t
Distance = ((0 + 20)/2) × 0.1
Distance = 1 m
Answer:
0.003034 s
1.035 m
4.5 m
Explanation:
= frequency of the tone = 329.6 Hz
= Time period of the sound wave
we know that, Time period and frequency are related as
= speed of the sound in the air = 341 ms⁻¹
wavelength of the sound is given as
= speed of the sound in the water = 1480 ms⁻¹
wavelength of the sound in water is given as
The answer for this would be B!!
Four of them pass a point every second.
Answer:
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