¿En qué campos de la investigación se llevan a cabo la mayor parte de técnicas relacionadas con la biotecnología?

Which statements describe how stars are born? Check all that apply. Stars are born in clouds of gas and dust called nebulas. The

prohojiy [21]

Answer: 1.Stars are born in clouds of gas and dust called nebulas.

2.The gas and dust are pulled together by gravity.

3.Heat and pressure cause nuclear fusion, which signals the birth of a star.

Explanation:

6 0

3 years ago

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Prevailing winds peru

VladimirAG [237]

In the afternoons the prevailing direction is South-East with recurrent low wind and calm that averages 30%. Overcast (cloudy): Lima has a lot of months under ...

3 0

3 years ago

Suppose that the gas-phase reactions A→B and B→A are both elementary processes with rate constants of 4.7×10−3s−1 and 5.8×10−1s−

uranmaximum [27]

Answer:

K = 8.1 x 10⁻³

Explanation:

We are told here that these gas phase reactions are both elementary processes, thus the reactions forward and reverse are both first order:

A→B Rate(forward) = k(forward) x [A]

and for

B→A Rate(reverse) = k(reverse) x [B]

At equilibrium we know the rates of the forward and reverse reaction are equal, so

k(forward) x [A] = k(reverse) x [B] for A(g)⇌B(g)

⇒ k(forward) / k(reverse) = [B] / [A] = K

4.7 x 10⁻³ s⁻1 / 5.8 x 10⁻¹ s⁻¹ = 8.1 x 10⁻³ = K

Notice how this answer is logical : the rate of the reverse reaction is greater than the forward reaction ( a factor of approximately 120 times) , and will be expecting a number for the equilibrium constant, K, smaller than one where the reactant concentration, [A], will prevail.

It is worth to mention that this is only valid for reactions which are single, elementary processes and not true for other equilibria.

8 0

3 years ago

How would you describe the rock cycle in your own words?

just olya [345]

A continuous process by which rocks are created, changed from one form to another, destroyed, and then formed again into different types of rocks. But what really know is that it's a rocky situation.

3 0

3 years ago

What volume (mL) of the sweetened tea described in Example 1 contains the same amount of sugar (mol) as 10 mL of the soft drink

S_A_V [24]

The question is incomplete, the complete question is:

What volume (mL) of the sweetened tea described in Example 3.14 contains the same amount of sugar (mol) as 10 mL of the soft drink in this example. The example is attached below.

Answer: 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

Explanation:

We first calculate the number of moles of soft drink in a volume of 10 mL

The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(1)

Taking the concentration of soft drink from the example be = 0.375 M

Volume of solution = 10 mL

Putting values in equation 1, we get:

$0.375=\frac{\text{Moles of sugar in soft drink}\times 1000}{10}\\\\\text{Moles of sugar in soft drink}=\frac{0.375\times 10}{1000}=0.00375mol$

Calculating volume of sweetened tea:

Moles of sugar = 0.00375 mol

Molarity of sweetened tea = 0.05 M

Putting values in equation 1, we get:

$0.05=\frac{0.00375\times 1000}{\text{Volume of sweetened tea}}\\\\\text{Volume of sweetened tea}=\frac{0.00375\times 1000}{0.05}=75mL$

Hence, 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

5 0

3 years ago