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Ad libitum [116K]
4 years ago
8

Determine the resultant horizontal and vertical force component that the water exerts on the side of the dam. The dam is 25 ft l

ong and specific weight = 62.4 ib/ft cubed. Diagram is located at:_________

Engineering
1 answer:
Leya [2.2K]4 years ago
3 0

Answer:

Your question is not complete. However, i have provided the missing part both the diagram and remaining data as stated in attached full.

Resultant vertical force component is 260005.2 Ibs

Resultant horizontal force component is 487500 Ibs

Explanation:

From P = Specific Weight * height

P = 62.4 * 25 = 1560Ib/ft^2

Then, W = P * Z

W = 1560 * 25 = 39000Ib/ft

Resultant forces

Let the base length be 10ft

A = 2/3 (a*b)

A = 2/3 (10* 25) = 166.67ft^2

Resolving vertical component

F vertical = Specific weight * Volume

F vertical = 62.4 (166.67 * 25)

F vertical = 260005.2 Ibs

Resolving horizontal component

F horizontal = 1/2 (W * height )

F horizontal = 1/2 ( 39000 *25)

F horizontal = 487500 Ibs

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5 0
3 years ago
Assume the work done compressing the He gas is -63 kJ and the internal energy change of the gas is 79 kJ. What is the heat loss
klemol [59]

Answer:

Heat gain of 142 kJ

Explanation:

We can see that job done by compressing the He gas is negative, it means that the sign convention we are going to use is negative for all the work done by the gas and positive for all the job done to the gas. With that being said, the first law of thermodynamics equation will help us to solve this problem.

ΔU = Q + W ⇒ Q = ΔU -W

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3 years ago
The mechanical properties of a metal may be improved by incorporating fine particles of its oxide. Given that the moduli of elas
mojhsa [17]

Answer:

A) Upper bound modulus of elasticity; E = 165.6 GPa

B) Lower bound modulus of elasticity; E = 83.09 GPa

Explanation:

A) Formula for upper bound modulus is given as;

E = E_m(1 - V_f) + E_f•V_f

We are given;

E_m = 60 GPa

E_f = 380 GPa

V_f = 33% = 0.33

Thus,

E = 60(1 - 0.33) + 380(0.33)

E = (60 x 0.67) + 125.4

E = 165.6 GPa

B) Formula for lower bound modulus is given as;

E = 1/[(V_f/E_f) + ((1 – V_f)/E_m)]

E = 1/[(0.33/380) + ((1 – 0.33)/60)]

E = 1/(0.0008684 + 0.01116667)

E = 1/0.01203507

E = 83.09 GPa

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