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Westkost [7]
2 years ago
5

Mobo, a wireless phone carrier, completed its first year of operations on October 31. All of the year's entries have been record

ed, except for the following: a. At year-end, employees earned wages of $6,000, which will be paid on the next payroll date, November 6. b. At year-end, the company had earned interest revenue of $3,000. It will be collected December 1 -4 Part 3 Show the accounting equation effects of each required adjustment. (Enter any decreases to Assets, Liabilities, or Stockholders' Equity with a minus sign.) ansaction Assets Liabilities Stockholders' Equity 6,000 Salaries and Wages Payable 4,900 6,000 alaries and Wages Expense nterest Receivable a. 4.,900 Acounts Payable b. terest Revenue
Engineering
1 answer:
kenny6666 [7]2 years ago
3 0

Answer:

Explanation:

a) Salaries and wages expenses     $6,000

   To salary for wages payable        $6,000

b) Interest Receivable a/c-d-               $4,900

   To interest revenue                          $4900

Assets   = Liabiliteies +stockholder equity

a)       0   =                 6000    +    (-6000)

    (No effect)        (Increase)   (Decrease)

       0 =6000 -6000

b)  4900  = 0      +          4900

                 (no effect)    (increase)

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An aggregate blend is composed of 55% aggregate A (Sp. Gr. 2.631), 25% aggregate B (Sp. Gr. 2.331) and 20% sand (Sp. Gr. 2.609).
Phoenix [80]

Answer:

The right choice would be Option b (2.545).

Explanation:

The given values are:

The aggregate blend will be:

W_A = 55%

G_ A = 2.631

W_ B = 25%

G_B = 2.331

W_C = 20%

G_C = 2.609

Now,

On applying the formula, we get

⇒ G_{BA}=\frac{W_A+W_B+W_C}{\frac{W_A}{G_A} +\frac{W_B}{G_B} +\frac{W_C}{G_C}}

On substituting the values, we get

⇒          =\frac{55+25+20}{\frac{55}{2.631} +\frac{25}{2.331} +\frac{20}{2.609}}

⇒          = \frac{100}{\frac{55}{2.631} +\frac{25}{2.331} +\frac{20}{2.609}}

⇒          =2.545

8 0
3 years ago
Distinguish between systems analysis and systems design?
Zielflug [23.3K]

Answer:

System analysis can be defined as a deep analysis of a part of the structure of a module that has been designed before. System design means to make any module or a part of the structure from scratch and build it completely without estimation.

Explanation:

3 0
3 years ago
1. A thin plate of a ceramic material with E = 225 GPa is loaded in tension, developing a stress of 450 MPa. Is the specimen lik
mina [271]

Answer:

fracture will occur as the value is less than E/10 (= 22.5)

Explanation:

If the maximum strength at tip Is greater than theoretical fracture strength value then fracture will occur and if the maximum strength is lower than theoretical fracture strength then no fracture will occur.

\sigma_m = 2\sigma_o [\frac{a}{\rho_t}]^{1/2}

=  2\times 750 (\frac{\frac{0.2mm}{2}}{0.001 mm}})^{1/2}

                 = 15 GPa

fracture will occur as the value is less than E/10 = 22.5

7 0
3 years ago
If the maximum allowable shear stress is 70 MPa, find the shaft diameter needed to transmit 40 kW when the shaft speed is 250 rp
victus00 [196]

Answer:

The diameter is 50mm

Explanation:

The answer is in two stages. At first the torque (or twisting moment) acting on the shaft and needed to transmit the power needs to be calculated. Then the diameter of the shaft can be obtained using another equation that involves the torque obtained above.

T=(P×60)/(2×pi×N)

T is the Torque

P is the the power to be transmitted by the shaft; 40kW or 40×10³W

pi=3.142

N is the speed of the shaft; 250rpm

T=(40×10³×60)/(2×3.142×250)

T=1527.689Nm

Diameter of a shaft can be obtained from the formula

T=(pi × SS ×d³)/16

Where

SS is the allowable shear stress; 70MPa or 70×10⁶Pa

d is the diameter of the shaft

Making d the subject of the formula

d= cubroot[(T×16)/(pi×SS)]

d=cubroot[(1527.689×16)/(3.142×70×10⁶)]

d=0.04808m or 48.1mm approx 50mm

7 0
3 years ago
Question 1 of 8.
Rasek [7]
The answer seems pretty obvious, all of the above
8 0
3 years ago
Read 2 more answers
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