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Ugo [173]
3 years ago
7

10. When an adhesion bond is made by melting a filler metal and allowing it to spread into the pores of the

Engineering
1 answer:
TEA [102]3 years ago
8 0
I believe the correct answer is “A”
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Technician A says automotive gasoline engines run on the 2 stroke principal. Technician B says Diesel engine hace less compressi
d1i1m1o1n [39]

Answer:

both are incorect

Explanation:

2 stroke principal is a mix of gasoline and engine oil a normal gasoline engine does not run on 2 stroke fuel

technician B is also wrong Diesel engines generally generate much higher compersion than gasoline engines

3 0
2 years ago
Select the correct answer.
boyakko [2]
I think the answer is b
6 0
3 years ago
Read 2 more answers
Based on the following passage on construction technology during the Middle Ages, why might a worker not be allowed
KonstantinChe [14]

Answer:

A guild are an association of skilled merchants, craftsmen and artisans that provide support and protection for their members and push their professional interest forward and further their craft

Because the guild guild members mainly gained their skill through knowledge passed to them by their family bloodlines, other unskilled workers were by not being schooled on the craft and by family tradition not allowed to join a guild based on the nature knowledge transfer the guild members have which is mainly several generations of family trade trainings

Explanation:

4 0
3 years ago
Read 2 more answers
We have a parallel-plate capacitor, with each plate having a width W and a length L. The plates are separated by air with a dist
Vesnalui [34]

Answer:

k

Explanation:

8 0
3 years ago
A tank contains initially 2500 liters of 50% solution. Water enters the tank at the rate of 25 iters per minute and the solution
sergejj [24]

Answer:

Percentage of solution=32. 96%

Explanation:

Given that initially tank have 50% solution.It means that amount of solution=0.5 x 2500 =1250 lts

Lets take the amount of solution at time t = A

So

\dfrac{dA}{dt}=rate\ in\ solution -rate\ out\ solution

\dfrac{dA}{dt}=concentration\times rate\ in\ of\ water -concentration\times rate\ out\ of\ water

\dfrac{dA}{dt}=0\times 25-\dfrac{A}{2500}\times 50

\dfrac{dA}{dt}=-\dfrac{A}{50}

Now by integration

\ln A=-\dfrac{1}{50}t+C

Where C is the constant

Given that at t=0 ,A=1250

So C=\ln 1250

\ln A=-\dfrac{1}{50}t+\ln 1250

When t=20 min

\ln A=-\dfrac{1}{50}\times 20+\ln 1250

A=837.90

So percentage of solution after 20 min

=\dfrac{1250-837.9}{1250}\times 100

Percentage of solution=32. 96%

4 0
3 years ago
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