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aleksandr82 [10.1K]
4 years ago
5

Will the body be travelling with a constant speed or a constant acceleration if the distance travelled by the body is directly p

roportional to time?
Physics
1 answer:
Anna35 [415]4 years ago
6 0
Distance ( say d ) is directly proportional to time ( say t ) .
mathematically ,
d = kt
where k is constant if proportionality .
Now differentiating the above equation with respect to time ,
we get ;
v = k
=> velocity is constant .
=> No acceleration .
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How much kinetic energy would a 65 kg person required to escape from the earth's gravitational field
stellarik [79]

The kinetic energy needed by the man is 4.5\cdot 10^9 J

Explanation:

The escape velocity (the speed needed by an object in the Earth's surface to escape the Earth's gravitational field) is given by

v=\sqrt{\frac{2GM}{R}}

where

G is the gravitational constant

M is the Earth's mass

R is the radius of the Earth

For the Earth, we have

M=5.97\cdot 10^{24} kg

R=6.37\cdot 10^6 m

Substituting, we find the escape velocity:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(5.97\cdot 10^{24})}{6.37\cdot 10^6}}=1.18\cdot 10^4 m/s

Now we can find the kinetic energy that the man would need, which is given by

K=\frac{1}{2}mv^2

where

m = 65 kg is the mass of the person

v=1.18\cdot 10^4 m/s is the escape velocity

Substituting,

K=\frac{1}{2}(65)(1.18\cdot 10^4)^2=4.5\cdot 10^9 J

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

3 0
4 years ago
Meteorologists study __________.
mezya [45]
They study weather and climate.
5 0
4 years ago
A coin is placed on a large disk which rotates uniformly at a rate of 1 rot/s. The coefficient of friction between the coin and
s2008m [1.1K]

Answer:

r = 0.02 m

Explanation:

from the question we have :

speed = 1 rps = 1x 60 = 60 rpm

coefficient of friction (μ) = 0.1

acceleration due to gravity (g) = 9.8 m/s^{2}

maximum distance without falling off (r) = ?

to get how far from the center of the disk the coin can be placed without having to slip off we equate the formula for the centrifugal force with the frictional force on the turntable force

mv^2 / r =  m x g x μ

v^2 / r =  g x μ  .......equation 1

where

velocity (v) = angular speed (rads/seconds) x radius

angular speed (rads/seconds) = (\frac{2π}{60} ) x rpm

angular speed (rads/seconds) = (\frac{2 x π}{60} ) x 60 = 6.28 rads/ seconds

now

velocity = 6.28 x r = 6.28 r

now substituting the value of velocity into equation 1

v^2 / r =  g x μ

(6.28r)^2 / r = 9.8 x 0.1

39.5 x r = 0.98

r = 0.02 m

6 0
3 years ago
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