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Lapatulllka [165]

1 year ago

8

A car travels 50 kilometers in 30 minutes. Which about the motion of the car are true?

1 answer:

irga5000 [103]1 year ago

6 0

Answer:

1500

Explanation:

is that all the question?

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The separation between two protons is increased by a factor of 2. How does the force between them change?

kramer

Decrease by a factor of 2

8 0

3 years ago

Mrs. Waid drives her car up Route 8 at 80mph. If her car weighs 2500 lbs,

Shtirlitz [24]

Answer:

It have 1.359 joule kinetic energy.

Explanation:

Kinetic energy is defined as the energy of any object due to its state of motion.
Mathematically kinetic energy can be calculated as:

K.E = $\frac{1}{2}$ $mv^{2}$ ...........................equation 1

where,

m= mass of object

v= velocity of that moving object

In the above problem;

mass= 2500 lbs = $5511.56$ kg.

velocity= 80mph= $\frac{80}{60*60}$ $m/s$ = $0.0222$ $m/s$ .

Substituting the values in equation 1, we get;

K.E= $\frac{1}{2}$ * $5511.56$ * $0.0222^{2}$

K.E= $1.359 joule.$

7 0

3 years ago

Cyclist A is moving at 20.0 m/s whereas cyclist B is moving at 12.0 m/s in the same direction and is initially ahead ofA. When t

stealth61 [152]

Answer:

$v_{fA} = 28 \frac{m}{s}$

Explanation:

The kinematic parameters from the moment the two cyclists begin to accelerate until they meet are:

Initial parameters:

$v_{oA} = 20 m/s$ : Initial speed of cyclist A

$v_{oB} = 12 m/s$ : Initial speed of cyclist B

Final parameters:

$v_{fB} = 20 m/s$ : Final speed of cyclist B

$d_{A} = d_{B}$

distance of cyclist A = distance of cyclist B

$t_{A} =t_{B} = 12s$

time of cyclist A = time of cyclist B

Cyclist B Kinematics

$v_{fB} = v_{oB} +a_{B} *t\\$

$36= 12 + a_{B} *12$

$a_{B} = \frac{36-12}{12}$

$a_{B} = 2 \frac{m}{s^{2} }$

$d_{B} =( v_{oB})*( t)+( \frac{1}{2} )*(a_{B})* (t)^{2}$

$d_{B} =( 12*(12)+( \frac{1}{2} )*(2)* (144)}$

$d_{B} = 288m$

Cyclist A Kinematics

$d_{A} =( v_{oA})*( t)+( \frac{1}{2} )*(a_{A})* (t)^{2}$

$d_{A} =(20*( 12)+( \frac{1}{2} )*(a_{A})* 144}$

$d_{A} = 240 + 72*(a_{A})$

$288=240+72*(a_{A} )$

$a_{A} = \frac{288-240}{72}$

$a_{A} = 0.67 \frac{m}{s^{2} }$

$v_{fA} = v_{oA} + a_{A} * t$

$v_{fA} = 20 + 0.67*12$

$v_{fA} = 28 \frac{m}{s}$

7 0

3 years ago

Is there any change in mass of substance after it changes its state? Explain with an example

Flura [38]

Answer:

No

Explanation:

When a substance changes its state , there will not be any change in the mass of substance . For example , if we change 100 grams of water (liquid) to ice(solid) , the mass of ice will be same i.e., 100 grams . This shows there is no change in the mass even if a substance changes its state.

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3 0

2 years ago

.<br><br> 1. True False<br> In AM waves, amplitude changes.

Dennis_Churaev [7]

That is true Step by step:

3 0

3 years ago

Read 2 more answers