Answer:
B) There are weak interactions between the CO2 molecules.
Explanation:
Carbon dioxide is composed of one carbon atom that is structured between two atoms of oxygen, they are bonded with double bond and the CO2 is symmetrical because of the arrangement of the bond between them.It is less electronegative than Oxgen, this gives Oxgen the ability to attract the electron to themselves, and there is no intermolecular existing within carbon dioxide other bands waal forces.Compounds that are gases under the condition of room temperatures, and pressure usually have have small molecules. and their molecules is usually have van der Waals forces acting between them and theses forces are weak.This allows carbon dioxide molecules to be able to move freely as a gas.
Answer:
0.653
Explanation:
1)
M1V1 = M2V2
M1 = 5.04 M
V1 = 229 mL ( you take only this volume)
V2 = 921 mL
5.04*229 = M2 * 921
M2 = (5.04*229)/921 Molarity
2)
M1V1 = M2V2
M1 = (5.04*229)/921
V1 = 100 mL
V2= 192 mL
(5.04*229)/921 *100 = M2 * 192
M2 = [(5.04*229)/921 *100]/192 = 0.653 final molarity
B, mode since mode represents the data is the most frequent in the whole set, which in this case is 8cm
When two distinct elements are chemically combined—i.e., chemical bonds form between their atoms—the result is called a chemical compound<span>. Most elements on Earth bond with other elements to form chemical compounds, such as sodium (Na) and Chloride (Cl), which combine to form table salt (NaCl).
Hope this helps.</span>
Answer:
The empirical formula is C3H3O
Explanation:
Step 1: Data given
Suppose the mass of the molecule = 100 grams
The molecule contains:
65.5 % Carbon = 65.5 grams
5.5 % Hydrogen = 5.5 grams
29.0% Oxygen = 29.0 grams
Molar mass of C = 12 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles C = 65.5 grams / 12 g/mol = 5.46 moles
Moles H = 5.5 / 1.01 g/mol = 5.45 moles
Moles O = 29.0 grams / 16 g/mol = 1.8125 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
C: 5.46 / 1.8125 = 3
H = 5.45 / 1.8125 = 3
O = 1.8125/1.8125 = 1
The empirical formula is C3H3O
