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Elodia [21]
4 years ago
14

After the collapse of a nebular cloud, atoms begin gravitating together to form a condensed center. What happens next in the sta

r formation process?
Physics
2 answers:
ELEN [110]4 years ago
8 0
Well, first of all, I don't think "After the collapse of a nebular cloud ..."
is the first time that "atoms begin gravitating together".  Seems to me like
that's what was going on all the time, and it's what caused the nebular cloud
to collapse in the first place.

In any case, once the pressure and temperature at the center get high enough,
you get "ignition" of nuclear fusion, and that's when you first have a "star". 
Otrada [13]4 years ago
5 0

Answer:

The core of the star is ignited.

Explanation:

Through the acummulation of mass caused by gravitation, the protostar becomes heavier and heavier until the pressure in its center, the core, is enough to initiate thermonuclear reactions. This reactions will be the source of the energy of the star during its entire life, as long as it shines.

The amount of mass needed for the protostar to ignite its core is known as stellar mass.

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Eight books, each 4.6 cm thick and of mass 1.8 kg, lie on a flat table. How much work work is required to stack them on top of o
pantera1 [17]

Answer:

529.92Newton Meters

Explanation:

Work=force x displacement

8books in total

force is 1.8kg

dispplacement is 4.6cm

times both units by 8 and u get

force - 14,4

displacement - 36.8

now times boht together and u get 529.92nm

3 0
2 years ago
Refraction occurs when a wave enters a new medium at an angle because
devlian [24]

Answer

The refracted wave must obey Snell's equation

Ni sin θi = Nr sin θr

If Nr differs from Ni then sin θr  will differ from sin θi

If the wave originates from point A and ends at point B then Snell's Law shows that the time for light to get from point A to point B is a minimum.

4 0
3 years ago
If a dog has the mass of 14.5kg and accelerates at a rate of 8m/sec2 →, If he runs into you what is the force he hits you with?
pashok25 [27]

Answer:

F=ma

m=14.5kg

a=8m/s^2

F=14.5×8

F=116N

Explanation:

PLS MARK BRAINLIEST

7 0
3 years ago
A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii. If the three of them are released simultaneou
Roman55 [17]

Answer:

The solid sphere will reach the bottom first.

Explanation:

In order to develop this problem and give it a correct solution, it is necessary to collect the concepts related to energy conservation. To apply this concept, we first highlight the importance of conserving energy so we will match the final and initial energies. Once this value has been obtained, we will concentrate on finding the speed, and solving what is related to the Inertia.

In this way we know that,

\Delta KE = - \Delta PE

KE_t + KE_r = mgh

We know as well that the lineal and angular energy are given by,

KE_r = \frac{1}{2}I\omega^2

And the tangential kinetic energy as

KE_t = \frac{1}{2} mv^2

Where\omega = \frac{v}{R}

Replacing

\frac{1}{2}mv^2 + \frac{1}{2}I\frac{v}{R} = mgh

Re-arrange for v,

v=\sqrt{\frac{2mgh}{m+I/R^2}}

We have here three different objects: solid cylinder, hollow pipe and solid sphere. We need the moment inertia of this objects and replace in the previous equation found, then,

For hollow pipe:

I_{hp}=mR^2

v_{hp}=\sqrt{\frac{2mgh}{m+(mR^2)/R^2}}

v_{hp}=\sqrt{\frac{2mgh}{m+m)}

v_{hp}=\sqrt{gh}

For solid cylinder:

I_{sc}=\frac{1}{2}mR^2

v_{sc}=\sqrt{\frac{2mgh}{m+(1/2mR^2)/R^2}}

v_{sc}=\sqrt{\frac{2mgh}{m+1/2m}}

v_{sc}=\sqrt{\frac{3}{4}gh}

For solid sphere,

I_{ss}=\frac{2}{5}mR^2

v_{ss}=\sqrt{\frac{2mgh}{m+(2/5mR^2)/R^2}}

v_{ss}=\sqrt{\frac{2mgh}{m+2/5m}}

v_{ss}=\sqrt{\frac{10}{7}gh}

Then comparing the speed of the three objects we have:

v_{hp}

\sqrt{gh}

3 0
4 years ago
An object is moving to the left with a constant speed. What can be concluded about the forces acting upon the object?
MariettaO [177]

Answer: sum of forces is zero

Explanation: acording to the newton first law you can say that the sum of the forces acting over the object is zero no matter the direction of movement

good luck

mario

8 0
3 years ago
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