Answer:
The second one
Step-by-step explanation:
ANSWER
(-3,3)
EXPLANATION
The given function is

Expand

Rewrite in the form:

This implies that,


Complete the square to get,




The function is now in the form:

where (h,k) =(-3,3) is the vertex
Answer:
23+5y=23x +5
5y=23x-18
y=23/5x - 18/5
<u>y--7=</u>23/5
x-6
5y+35=23x-138
5y=23x-203
y=23/5x -203/5
Step-by-step explanation:
Answer:
Step-by-step explanation:
first graph
<h2>height=constant* width ( direct variation describes a linear relation between 2 variable )</h2>
6=8x ⇒ x=6/8=0.75
h=0.75w
<h2>constant is 0.75</h2>
second graph:
<h2>height=constant/width ( inverse variation)</h2>
15=x/4 ⇒x=4*15 ⇒x=60
<h2>constant=60</h2>
For two quantities with inverse variation, as one quantity increases, the other quantity decreases. k(constant)=xy