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miss Akunina [59]
3 years ago
13

What is a factor of 5x2 - 15x - 20a.) x+3b.) x + 4c.) x - 5d.) x+1

Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0

I believe the answer is C.

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Heidi hikes two trails, the Big Trapezoid and the Little Trapezoid. The shorter base of the Big Trapezoid is 2 mi long, while th
Ivenika [448]
If the shapes are similar and the smaller trapezoid's long base is half of the big trapezoid's long base than that means that the small trapezoid's short base would be half of the big trapezoid's short base.

Answer: The Little Trapezoid's shorter base is 1 mi long.

I hope this helps.
8 0
3 years ago
Ok so i need the work and answer for this problem is due asap click the picture.
IRISSAK [1]

Answer:

C. 36

Step-by-step explanation:

There are 217 students and 35 adults.

217 + 35 = 252 people

There are 7 buses for 252 people

252 people ÷ 7 buses = 36 people per bus

7 0
3 years ago
Read 2 more answers
Which is a solution to 2x + 1 = 21?
Bezzdna [24]

Answer:

x = 10 is your answer

- Explain -

Step 1: subtract 1 from both sides (subtraction of equality)

which will give us:

2x = 21 - 1

which equals to

2x = 20

Step 2: Divide both sides by 2

which is

2x/2 = 20/2

2/2 = 1 and 20/2 = 10

Therefore the answer is x = 10

4 0
3 years ago
Which steps could be used to solve this story problem?
kap26 [50]
B........................
3 0
3 years ago
Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).
ale4655 [162]

Answer:

The required equation is:

y = -\frac{3}{2}x+9

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)

We will find the slope of given line segment first

m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{2-10}{-4-8}\\=\frac{-8}{-12}\\=\frac{2}{3}

Let m_1 be the slope of perpendicular bisector then,

m.m_1 = -1\\\frac{2}{3}.m_1 = -1\\m_1 = \frac{-3}{2}

Now the mid-point

(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\= (\frac{8-4}{2} , \frac{10+2}{2})\\=(\frac{4}{2}, \frac{12}{2})\\=(2,6)

We have to find equation of a line with slope -3/2 passing through (2,6)

The equation of line in slope-intercept form is given by:

y = m_1x+b

Putting the value of slope

y= -\frac{3}{2}x+b

Putting the point (2,6) to find the y-intercept

6 = -\frac{3}{2}(2)+b\\6 = -3+b\\b = 6+3 =9

The equation is:

y = -\frac{3}{2}x+9

7 0
3 years ago
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