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Nataly_w [17]
4 years ago
6

The electrons are found outside the nucleus and have a _______________ charge?

Chemistry
2 answers:
Alinara [238K]4 years ago
8 0
Electrons have a negative charge 
sladkih [1.3K]4 years ago
3 0
The answer is Negatively Charge, correct me if i'm wrong :)
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Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
6 0
4 years ago
What are the name for : BeCl2.2H20 and LiNO2.H20
brilliants [131]
BeCl2 = Beryllium Chloride
2H2O = 2 molecules of H2O (water)
LiNO2 = Lithium Nitrate
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5 0
3 years ago
Read 2 more answers
What is the energy of a photon of violet light with a frequency of 7.57x10^14 s^-1?
Eddi Din [679]

Answer:

ΔE = 5.02 x 10⁻¹⁹ j

Explanation:

ΔE (photon) = h·f = (6.63 x 10⁻³⁴ j·s)(7.57 x 10¹⁴ s⁻¹) = 5.02 x 10⁻¹⁹ j

h = Planck's Constant = 6.63 x 10⁻³⁴ j·s

f = frequency (given) = 7.57 x 10¹⁴ s⁻¹

6 0
3 years ago
Which of the following can be detected by forensic light sources
ss7ja [257]

Answer:

A forensic light source is a crime scene investigator's and lab technician's tool for enhancing observation, photography and collection of evidence including latent fingerprints, body fluids, hair and fibers, bruises, bite marks, wound patterns, shoe and foot imprints, gun shot residues, drug traces, questioned

4 0
3 years ago
2Al+6HBr -> 2AlBr3+3H2. When 3.22 moles of Al reacts with 4.96 moles of HBr, how many moles of H2 are formed?
Cerrena [4.2K]
<span>2 Al+6 HBr =  2 AlBr</span>₃ <span>+ 3 H</span>₂

2 moles Al ---------  6 moles HBr ----------- 3 moles H₂
3.22 moles Al ------ 4.96 moles HBr ----- ( moles H₂ )

moles H₂ = 4.96 x 3 / 6

moles H₂ = 14.88 / 6

= 2.48 moles of H₂

hope this helps!
4 0
3 years ago
Read 2 more answers
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