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horrorfan [7]
4 years ago
8

Which statement about the effects of medium on the speed of a mechanical wave is true?

Physics
1 answer:
Anastasy [175]4 years ago
7 0

C. A mechanical wave generally travels faster in gases than liquids.

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A distracted driver is driving towards a turn where the edge of the road leads into a 75.0 m cliff. The velocity of the vehicle
Vlada [557]

As long as the car is on the road, it moves with a constant speed of 80km/h.

As soon as the car starts to fall down the cliff, it follows a parabolic motion. It means that it still moves with constant speed along the x axis, but it also starts to move along the y axis, with constant acceleration (i.e. the acceleration due to gravity).

The good thing about parabolic motions is that the two motions along the x and y axes are completely separable.

So, first of all, we need to know how long it takes for an object to fall for 75m. The equation of a constantly accelerated motion is

s=s_0+v_0t+\dfrac{1}{2}at^2

Where s_0 is the initial position, v_0 is the initial speed, and a is the constant rate of acceleration. In our case, we start from an initial height of 75m, an initial (vertical!) speed of zero, and our acceleration is -g. So, our equation becomes

s=75-\dfrac{g}{2}t^2

And we want to solve for the time when s=0 (i.e. we want to know how long will it take for the object to reach the ground). We have

0=75-\dfrac{g}{2}t^2 \iff 75=\dfrac{g}{2}t^2 \iff \dfrac{2\cdot75}{g}=t^2 \iff t=\sqrt{\dfrac{150}{g}}

(I'm discarding the negative solution because it wouldn't make sense)

Now that we've used the vertical motion to find out the falling time, we can go back to the horizontal motion. We know that the car moves for a certain amount of time at a certain speed. So, we simply have to plug our values in the s=vt equation, to get

s=80\sqrt\dfrac{150}{g}}

This is how far from the base of the cliff the vehicle lands.

3 0
3 years ago
X-rays cannot pass through Earth's atmosphere. Which of these is the best location to place a telescope used to observe x-rays f
Amiraneli [1.4K]
Mountains, tops of buildings, and high-flying aircraft are all part of Earth's atmosphere, no matter how high they are. On the other hand, space doesn't belong to our atmosphere, it is outside of it. Having this in mind, the best location to place a telescope used to observe x-rays from stars is in space.
7 0
3 years ago
Read 2 more answers
A neutron star is an extremely dense, rapidly spinning object that results from the collapse of a massive star at the end ofits
Westkost [7]

Answer:

(a). The rotational inertia is 5.72\times10^{39}\ kg m^2

(b). The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

Explanation:

Given that,

Mass of neutron M_{n}= 13M_{s}

Density of neutron \rho=4.8\times10^{17}\ kg/m^3

(a). We need to calculate the rotational inertia

Using formula of rotational inertia  for sphere

I=\dfrac{2}{5}MR^2...(I)

We know that,

\rho=\dfrac{M}{V}

Put the value of volume

\rho=\dfrac{3M_{n}}{4\pi R^3}

R^2=(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}

Put the value of R in equation (I)

I=\dfrac{2}{5}\times M_{n}\times(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}

Put the value into the formula

I=\dfrac{2}{5}\times(13\times2\times10^{30})^{\frac{5}{3}}\times(\dfrac{3}{4\pi\times(4.8\times10^{17})})^{\frac{2}{3}}

I=5.72\times10^{39}\ kg m^2

The rotational inertia is 5.72\times10^{39}\ kg m^2.

(b). We need to calculate the magnitude of the magnetic torque

Using formula of torque

\tau=I\times \alpha

Put the value into the formula

\tau=5.72\times10^{39}\times5.6\times10^{-5}

\tau=3.20\times10^{35}\ N-m

The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

Hence, (a). The rotational inertia is 5.72\times10^{39}\ kg m^2

(b). The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

4 0
3 years ago
If a thermometer reads 52° F, what is the temperature in Celsius?
defon

Answer:

11.11 C

Explanation:

(52 f-32) * 5/9= 11.11

7 0
3 years ago
Read 2 more answers
You are using a bucket of water in a science experiment. You conclude that water is a liquid because
Harrizon [31]
Well you could see it's physical properties have the same descriptions corresponding to a liquid. (Sorry if this doesn't help you..)
8 0
4 years ago
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