Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

$d=vt+\frac{1}{2}at^2$

Now by substituting values in, we get

$d=(0\frac{m}{s})*(2.01s)+\frac{1}{2}(9.8\frac{m}{s^2})(2.01)^2$

d = 19.796m

7 0

3 years ago

A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then

Alexeev081 [22]

Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

Weight = 0.71 N

Water level = 50 mL

object inserted = 75 mL

We need to calculate the volume of solid

Using formula of volume

$V=25\ ml = 25\times10^{-6}\ m^3$

We need to calculate the buoyancy force

Using formula of buoyancy force

$F'= V\rho g$

Put the value into the formula

$F'=25\times10^{-6}\times1000\times9.8$

$F'=0.245\ N$

We need to calculate the apparent weight of the object

Using formula of apparent weight

$W=F-F'$

Put the value into the formula

$W=0.71-0.245$

$W=0.465\ N$

Hence, The apparent weight of the object is 0.465 N.

5 0

2 years ago