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Jobisdone [24]
3 years ago
15

What is the difference between a low tide and a high tide

Physics
2 answers:
Savatey [412]3 years ago
6 0
A high tide means when the water has risen and is higher up(closer to high up land). Low tide is when it’s receded
Oxana [17]3 years ago
5 0

Answer:

High water level during a tide is called High tide.

Low water level during a tide is called Low tide.

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Hannah has information about an object in circular orbit around Earth.
Elena-2011 [213]

The correct answer is:

the distance of the orbiting object to Earth.

In fact, we know that the gravitational force that keeps the object in circular motion around the Earth is equal to the centripetal force, so we can write:

G\frac{Mm}{r^2}=m\frac{v^2}{r}

If we re-arrange the equation, we find an expression for the tangential speed of the object:

v=\sqrt{\frac{GM}{r}}

and we see that it depends on 3 quantities: G, M (the mass of the Earth) and r (the distance of the object from the Earth).

3 0
3 years ago
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If a person looking at a poster sees green instead of yellow and doesn't see red at all, this person most likely has color blind
katrin [286]
Red - sensitive so answer is c
7 0
3 years ago
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When two waves undergo complete, constructive interference, which of the following increases ?
Lostsunrise [7]
A speed cause it would slow down meeting eachother
4 0
4 years ago
If a small sports car collides head-on with a massive truck, which vehicle experiences the greater impact force? Which vehicle e
garri49 [273]

Answer:

Small sports car.

Explanation:

Lets take

mass of the small car = m

mass of the truck = M

As we know that when car collide with the massive truck then due to change in the moment of the car both car as well as truck will feel force.We also know that from Third law of Newton's ,it states that every action have it reaction with same magnitude but in the opposite direction.

Therefore

F = m a

a=Acceleration of the car

a=\dfrac{F}{m}

F= M a'

a'=Acceleration of the massive truck

a'=\dfrac{F}{M}

Here given that M > m that is why a > a'

Therefore car will experiences more acceleration.

5 0
3 years ago
On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the
Nina [5.8K]

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

\frac{F_E}{F_G}=\frac{qE}{mg}              (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764

Then, the gravitational force is 0.764 times the electric force on the particle

b)

The acceleration of the particle is obtained by using the second Newton law:

F_E-F_G=ma\\\\a=\frac{qE-mg}{m}

you replace the values of all variables:

a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

7 0
3 years ago
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