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Mariulka [41]
3 years ago
13

4. Which of the following statement is correct regarding velocity and speed of a moving body?

Physics
2 answers:
Jlenok [28]3 years ago
8 0

Answer:

d

Explanation:

Velocity is the same as speed except it's a vector quantity which means it has a direction.

lara31 [8.8K]3 years ago
7 0

Answer:

Explanation:

Hello friend!!!

The correct option is <u><em>(d) Velocity of a moving body is its speed in a given direction.</em></u>

Hope this helps

plz mark as brainliest!!!!!!!!

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Four 50-g point masses are at the corners of a square with 20-cm sides. What is the moment of inertia of this system about an ax
deff fn [24]

Answer:

moment of inertia I ≈ 4.0 x 10⁻³ kg.m²

Explanation:

given

point masses = 50g = 0.050kg

note: m₁=m₂=m₃=m₄=50g = 0.050kg

distance, r, from masses to eachother = 20cm = 0.20m

the distance, d, of each mass point from the centre of the mass, using pythagoras theorem is given by

= (20√2)/ 2 = 10√2 cm =14.12 x 10⁻² m  

moment of inertia is a proportion of the opposition of a body to angular acceleration about a given pivot that is equivalent to the entirety of the products of every component of mass in the body and the square of the component's distance from the center

mathematically,

I = ∑m×d²

remember, a square will have 4 equal points

I = ∑m×d² = 4(m×d²)

I = 4 × 0.050 × (14.12 x 10⁻² m)²

I = 0.20 × 1.96 × 10⁻²

I =  3.92 x 10⁻³ kg.m²

I ≈ 4.0 x 10⁻³ kg.m²

attached is the diagram of the equation

7 0
3 years ago
a backpack has a mass of 8 kg. it is lifted and given 54.9 J of gravitational potential energy. how high is is lifted? accelerat
dalvyx [7]
P=mgh
h=P/mg
h=(54.9)/(8*9.8)= 0.7m
8 0
3 years ago
A 65 kg students is walking on a slackline, a length of webbing stretched between two trees. the line stretches and sags so that
polet [3.4K]

Answer : Tension in the line = 936.7 N

Explanation :

It is given that,

Mass of student, m = 65 kg

The angle between slackline and horizontal, \theta=20^0

The two forces that acts are :

(i) Tension

(ii) Weight

So, from the figure it is clear that :

mg=2T\ sin\ \theta

T=\dfrac{mg}{2\ sin\theta}

T=\dfrac{65\ kg\times 9.8\ m/s^2}{2(sin\ 20)}

T=936.7\ N

Hence, this is the required solution.

5 0
3 years ago
Read 2 more answers
What mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 ∘C? The heat of vaporization of water at
romanna [79]

Answer:

100 cc

Explanation:

Heat released in cooling human body by t degree

= mass of the body x specific heat of the body x t

Substituting the data given

Heat released by the body

= 70 x 3480 x 1

= 243600 J

Mass of water to be evaporated

= 243600 / latent heat of vaporization of water

= 243600 / 2420000

= .1 kg

= 100 g

volume of water

= mass / density

= 100 / 1

100 cc

1 / 10 litres.

6 0
3 years ago
What will be the new volume when 128 mL of gas at 20.0°C is heated to 40.0°C while pressure remains unchanged? What will be the
soldier1979 [14.2K]

The answer will be 137 mL

7 0
3 years ago
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