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AVprozaik [17]
2 years ago
8

The degree of unsaturation, or index of hydrogen deficiency, is the number of pi bonds plus rings in a molecule. Specify the deg

ree of unsaturation (index of hydrogen deficiency) of the following formulas:
(a) C5H6
(b) C10H6Cl2
(c) C4H3NO
Chemistry
1 answer:
yaroslaw [1]2 years ago
5 0

Explanation:

The degree of unsaturation is given as;

Degree of unsaturation = (2C + 2 + N - H - X) / 2

(a) C5H6

Using the formular above;

Degree of unsaturation = [ 2(5) + 2 - 6] / 2

Degree of unsaturation = [ 12 - 6 ] / 2 = 3

(b) C10H6Cl2

Using the formular above;

Degree of unsaturation = [ 2(10) + 2 - 6 -2 ] / 2

Degree of unsaturation = [ 22 - 8 ] / 2 = 7

(c) C4H3NO

Using the formular above;

Degree of unsaturation = [ 2(4) + 2 - 3 -1 ] / 2

Degree of unsaturation = [ 10 - 4 ] / 2 = 3

Note: Oxygen is ignored because its presence has no effect on the degree of unsaturation.

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I think it's 8g

Explanation:

I think this is the answer

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Number of moles of Sn (l) produced when 4.0 moles of H2 (g) is completely consumed
Dafna11 [192]
The answer is 2.0 moles.
From their coefficients in the balanced chemical equation below for the reaction of tin dioxide with hydrogen gas to produce tin and water:
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4 0
3 years ago
rutherford's experiment with gold estimate the radius of a gold atom to be approximately 1x10^-9 cm. Suppose the radius of the n
Lemur [1.5K]
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3 0
3 years ago
While performing the assays for the LDH kinetics experiment, you will pipet 25ul of 250 ug/ml LDH into 975 ul of assay buffer (T
ArbitrLikvidat [17]

Answer:

6.25 μg/mL

Explanation:

When a dilution is made, the mass of the solute is conserved (Lavoiser's law), so the mass pipetted will be the mass in the assay. The mass is the concentration (C) multiplied by the volume (V). If the pipet solution is called 1, and the assay 2:

m1 = m2

C1*V1 = C2*V2

C1 = 250 μg/mL

V1 = 25 μL

V2 = 975 μL + 25 μL = 1000 μL (is the final volume of the assay after the addition of LDH)

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6 0
3 years ago
How many grams of sulfur must be burned to give 100.0 g of So2
andriy [413]

Answer:

50 g of S are needed

Explanation:

To star this, we begin from the reaction:

S(s) + O₂ (g) →  SO₂ (g)

If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.

According to stoichiometry, we can determine the moles of sulfur dioxide produced.

100 g. 1mol / 64.06g = 1.56 moles

This 1.56 moles were orginated by the same amount of S, according to stoichiometry.

Let's convert the moles to mass

1.56 mol . 32.06g / mol = 50 g

4 0
3 years ago
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