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vampirchik [111]
3 years ago
6

A model rocket flies horizontally off the edge of a cliff at a velocity of 50.0 m/s. If the canyon below is 100.0 m deep, how fa

r in the horizontal direction does the rocket travel from the edge of the cliff? (Assume no air resistance and that a^y=g=9.81 m/s^2.).
A. 226 m
B. 245 m
C. 350 m
D. 526 m
Physics
1 answer:
padilas [110]3 years ago
5 0

If the canyon below is 100.0 m deep, the rocket travels from the edge of the cliff 226m in the horizontal direction.

 

<span>When </span>air resistance<span> acts, acceleration during a fall will be less than g because </span>air resistance affects<span> the motion of the falling objects by slowing it down. </span>Air resistance<span> depends on two important factors - the speed of the object and its urface area. Increasing the surface area<span> of an object decreases its speed.</span></span>

 

The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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Sergio [31]

1. Due to the first law of Newton: there is a force that accelerate the body,

then the net force for 2 forces in opposite directions can calculated as

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F_{x}=Fsin ( θ )= 67sin(73)=64N

then, as Q(1),

F_{net}=F_{1}-F_{2}=64-33=31 N

3. Because of the non change in the velocity, there is no acceleration

Then, there is no force is acted from the body

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F_{x}=Fsin ( θ )= 600sin(45)=424.264N

F_{y} = F sin ( θ )= 600cos45)=424.264N

Hence we have 2 opposite horizontal forces. also, 2 opposite vertical forces.

now, we calculate the net forces in each direction

F_{net in x}=F_{1}-F_{2}=424.264-250=174.264 N in east

F_{net in y}=F_{1}-F_{2}=-500-424.264=75.736 N in south

The total net force for perpendicular forces is calculated from the relation:  

F_{total}=\sqrt{F_{x} ^{2}+F_{y}^{2}}=\sqrt{174.264^{2}+75.736^{2}}=190N

B) To find the direction, we need to calculate the angle which the total force is made with the east direction of the x-axis (horizontal)

θ = tan^{-1}(\frac{F_{y}}{F_{x} })= tan^{-1}(\frac{-75.736}{174.264})=-23.48^{o}

That meas that the total force is made with the east direction of the x-axis angle equal to 23.48 for the south (the 4th quarter)

5. According to the third law of Newton, to make the balance the net force  equal to zero (for each action there is a reaction with the same amplitude and in opposite direction)

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igomit [66]
Angular magnifiction=m= \frac{ f_{0} }{ f_{e} }
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Answer:

Temporary? You have two options

If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).

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Answer:

Explanation:

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Answer:

Quiet, is the adjective in this sentence

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