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vodomira [7]
3 years ago
10

a student performed an analysis of a sample for it's calcium content and got the following results: 14.92%, 14.91%, 14.88%, 14.9

1%. The actual amount of calcium in the sample is 15.70%. What conclusion can you draw about the accuracy and precision of these results?
Chemistry
1 answer:
kramer3 years ago
5 0
The question is asking to state the conclusion that can be formulated, base on the problem or the given analysis of the data, about the accuracy and precision  and base on my research, i would say that the Accuracy is Poor but the Precision is Good. I hope this would help you 
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Sodium hydrogen carbonate NaHCO3 , also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. A
FromTheMoon [43]

Answer:

<em>The mass of NaHCO₃ that the man would need to ingest to neutralize this much HCl is 0.059 g.</em>

<em />

Explanation:

1) <u>Chemical equation (given)</u>:

  • HCl (aq) + NaHCO₃ (aq) → NaCl (aq) + H₂O (l) + CO₂ (g)

Both sides have the same number of atoms of each element:

Element       Let side      Right side

H                  1 + 1 = 2       1 × 2 = 2

Cl                 1                   1

Na                1                   1

C                  1                   1

O                 3                   1 + 2 = 3

Hence, the equation is balanced.

2. <u>Mole ratios:</u>

<u />

  • 1 mol HCl  : 1 mol NaHCO₃ : 1 mol NaCl : 1 mol H₂O : 1 mol CO₂

2)<u> Determine the number of moles of HCl in solution</u>:

  • M = n / V (liters) ⇒ n = M × V (liters)
  • V (liters) = 200.mL (1 liter / 1000 mL) = 0.200 liter
  • n = 0.035 M  × 0.200 liter = 0.00070 mol of HCl

3) <u>Set a proportion with the stoichiometric ratio and the actual ratio</u>:

  • 1 mol NaHCO₃ / 1 mol HCl = x / 00070 mol HCl

        ⇒ x = 0.00070 mol NaHCO₃

4.<u> Convert 0.0070 mol NaHCO₃ to grams</u>:

  • Mass in grams = molecular mass × number of moles
  • molecular mass NaHCO₃ = 84.007 g/mol
  • Mass of NaHCO₃ = 84.007 g/mol × 0.00070 mol = 0.0588 g ≈ 0.059 g

The answer has two significant digits because the molarity (0.035 M) is reported with two signficant digits.

8 0
3 years ago
How many milliliters of 2.5 M HCl are required<br> to exactly neutralize 1.5 L of 5.0 M NaOH?
Airida [17]

Answer:

3000mL

Explanation:

The following data were obtained from the question:

Volume of acid (Va) =..?

Molarity of acid (Ma) = 2.5M

Volume of base (Vb) = 1.5L

Molarity of base (Mb) = 5M

Next, we shall write the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

We obtained the following:

Mole ratio of the acid (nA) = 1

Mole ratio of base (nB) = 1

Next, we shall determine the volume of HCl needed for the reaction. This can be obtained as follow illustrated below:

MaVa / MbVb = nA/nB

2.5 x Va / 5 x 1.5 = 1

Cross multiply

2.5 x Va = 5 x 1.5

Divide both side by 2.5

Va = 5 x 1.5 / 2.5

Va = 3L

The volume of the acid required is 3L.

Finally, we shall convert the volume of the acid from litre (L) to millilitre (mL). This is illustrated below:

1L = 1000mL

Therefore, 3L = 3 x 1000 = 3000mL.

Therefore, the volume of the acid, HCl in mL needed fi4 the reaction is 3000mL

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What ions make up the ionic compound FeCrO4 ?
aksik [14]

Answer:

metals and nonmetals

Explanation:

that's your answer have a nice day

3 0
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