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Tcecarenko [31]
3 years ago
14

Two identical point charges q=71.0 pCq=71.0 pC are separated in vacuum by a distance of 2d=29.0 cm.2d=29.0 cm. Calculate the tot

al electric flux ΦΦ through the infinite surface placed at a distance dd from each charge, perpendicular to the line on which the point charges are located.
Physics
1 answer:
Andreyy893 years ago
4 0

Answer:

The electric flux at the infinite surface is ZERO

Explanation:

From the question we are told that  

    The point charge are identical and the value is  q = 71.0 pC =  71 * 10^{-12} \ C

    The distance of separation is  D =  29.0 \ cm  =  0.29 \ m

    The distance of both from the infinite surface is  d

Generally the electric force exerted by each of the  charge on the infinite surface is

       \phi =  \frac{q}{\epsilon_o}

Now given from the question that they are identical, it then means that the electric flux of the first charge on the infinite surface will be nullified by the electric flux of the second charge hence the electric flux at that infinite surface due to this two identical charges is ZERO

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According to Coulomb’s Law, what happens to the force when the distance increase between 2 particles?
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Answer:

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Explanation:

Coulomb’s law, mathematical description of the electric force between charged objects. Formulated by the 18th-century French physicist Charles-Augustin de Coulomb, it is analogous to Isaac Newton’s law of gravity.

Both gravitational and electric forces decrease with the square of the distance between the objects, and both forces act along a line between them. In Coulomb’s law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. Thus, charge determines how electromagnetism influences the motion of charged objects. Charge is a basic property of matter. Every constituent of matter has an electric charge with a value that can be positive, negative, or zero.

Coulomb's Law says that the force between 2 charges is proportional to the product of the quantities of charge on each and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is F=k\frac{q_{1}q_{2}   }{r^{2} }.

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q_{2} is the electric charge of object 2.

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Electric force is inversely proportional to (r^{2}) instead of (r). As the distance between charges increases, the electric force decreases by a factor of \frac{1}{r^{2} }.

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Answer:

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