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Tcecarenko [31]
3 years ago
14

Two identical point charges q=71.0 pCq=71.0 pC are separated in vacuum by a distance of 2d=29.0 cm.2d=29.0 cm. Calculate the tot

al electric flux ΦΦ through the infinite surface placed at a distance dd from each charge, perpendicular to the line on which the point charges are located.
Physics
1 answer:
Andreyy893 years ago
4 0

Answer:

The electric flux at the infinite surface is ZERO

Explanation:

From the question we are told that  

    The point charge are identical and the value is  q = 71.0 pC =  71 * 10^{-12} \ C

    The distance of separation is  D =  29.0 \ cm  =  0.29 \ m

    The distance of both from the infinite surface is  d

Generally the electric force exerted by each of the  charge on the infinite surface is

       \phi =  \frac{q}{\epsilon_o}

Now given from the question that they are identical, it then means that the electric flux of the first charge on the infinite surface will be nullified by the electric flux of the second charge hence the electric flux at that infinite surface due to this two identical charges is ZERO

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Answer:

Explanation:

Given

When we drop an object from height , suppose h

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h=ut+\frac{1}{2}at^2

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t=time

here u=0 because it dropped from a certain height

h=\frac{1}{2}gT^2

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When height is increases to three times of original height

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3 years ago
The dial of a scale looks like this: 00.0kg. A physicist placed a spring on it. The dial read 00.6kg. He then placed a metal cha
saveliy_v [14]

Answer:

d. The scale's resolution is too low to read the change in mass

Explanation:

If we want to find the change in energy of the spring, we will have to use the Hooke's Law. Hooke's Law states that:

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since,

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integrating and using value of F, we get:

ΔE = (0.5)kx²

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ΔE = Energy added to spring

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The spring constant is typically in range of 4900 to 29400 N/m.

So if we take the extreme case of 29400 N/m and lets say we assume an unusually, extreme case of 1 m compression, we get the value of energy added to be:

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ΔE = 1.47 x 10⁴ J

Now, if we convert this energy to mass from Einstein's equation, we get:

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Δm = ΔE/c²

Δm = (1.47 x 10⁴ J)/(3 x 10⁸ m/s)²

<u>Δm =  4.9 x 10⁻¹³ kg</u>

As, you can see from the answer that even for the most extreme cases the value of mass associated with the additional energy is of very low magnitude.

Since, the scale only gives the mass value upto 1 decimal place.

Thus, it can not determine such a small change. So, the correct option is:

<u>d. The scale's resolution is too low to read the change in mass</u>

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jek_recluse [69]

Answer:

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The multiple reflection of a single sound wave is a/an
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A single reflection, like shouting at the side of a mountain and hearing
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