C because
You have to have a question then research and arrive to a conclusion
Calculate the pressure due to sea water as density*depth.
That is,
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa
Atmospheric pressure is 101.3 kPa
Total pressure is 94423 + 101.3 = 94524 kPa (approx)
The area of the window is π(0.44 m)^2 = 0.6082 m^2
The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
(a) 3675 N
Assuming that the acceleration of the rocket is in the horizontal direction, we can use Newton's second law to solve this part:

where
is the horizontal component of the force
m is the mass of the passenger
is the horizontal component of the acceleration
Here we have
m = 75.0 kg

Substituting,

(b) 3748 N, 11.3 degrees above horizontal
In this part, we also have to take into account the forces acting along the vertical direction. In fact, the seat exerts a reaction force (R) which is equal in magnitude and opposite in direction to the weight of the passenger:

where we used
as acceleration of gravity.
So, this is the vertical component of the force exerted by the seat on the passenger:

and therefore the magnitude of the net force is

And the direction is given by

A )voltage
(i.e differance in electricity field)
Answer: type of force is friction
Explanation: