All categories

2 years ago

What is the chemical formula for ammonium carbonate?

Chemistry

1 answer:

ivann1987 [24]2 years ago

7 0

Answer:

(NH4)2CO3

Explanation:

google

You might be interested in

Could someone help me with this?

Varvara68 [4.7K]

Solving part-1 only

KMnO_4

Transition metal is Manganese (Mn)

Actually it's the oxidation number of Mn

Let's find how?

$\\ \tt\Rrightarrow x+1+4(-2)=0$

$\\ \tt\Rrightarrow x+1-8=0$

$\\ \tt\Rrightarrow x-7=0$

$\\ \tt\Rrightarrow x=+7$

x is the oxidation number

Purple as per the color of potassium permanganate

$\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}$

7 0

1 year ago

A block of iron has a mass of 150 g and a volume of 20 ml. What is the density of iron? *

shtirl [24]

Answer:

<h3>The answer is 7.50 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of iron = 150 g

volume = 20 mL

We have

$density = \frac{150}{20} = \frac{15}{2} \\$

We have the final answer as

Hope this helps you

4 0

2 years ago

Read 2 more answers

Write a balanced equation formed when the following elements react with oxygen:a)Zinc

Ainat [17]

Explanation:

a) when zinc burnt in oxygen.

2Zn + O2 -----∆-----> 2ZnO(black residue)

b) when carbon burnt in oxygen.

C+O2----∆---> CO2.

c) when sulphur burnt in oxygen.

S+O2-----∆-----> SO2.

d) when Calcium burnt in oxygen.

2Ca+O2-----∆-----> 2CaO(black residue)

e) when Magnesium burnt in oxygen.

2Mg+O2-----∆----> 2MgO.

f) when sodium burnt in oxygen.

4Na+O2----∆-----> 2Na2O.

hope all these reactions help you.

4 0

2 years ago

What does the last line of the poem suggest

Klio2033 [76]

Answer:

that the poem needs to be finished heh pog

Explanation:

7 0

2 years ago

Read 2 more answers

Please help on question nine

gregori [183]

Put one thousand becaus it says one thousand :) your welcome

6 0

3 years ago