<span>Molecules are speeding up during boiling. Is the correct answer this question.</span>
Answer: The value of equilibrium constant for reaction is,
Explanation:
The given chemical equations are:
(1)
;
(2)
; 
Now we have to calculate the equilibrium constant for chemical equation as:
; 
We are reversing reaction 2 and multiplying reaction 2 by 2 and then adding both reaction, we get the final reaction.
The equilibrium constant for the reverse reaction will be the reciprocal of that reaction.
If the equation is multiplied by a factor of '2', the equilibrium constant of that reaction will be the square of the equilibrium constant.
If we are adding equations then the equilibrium constants will be multiplied.
The value of equilibrium constant for reaction is:

Now put all the given values in this expression, we get:


Hence, the value of equilibrium constant for reaction is,
The reaction involved in present case is:
Net Reaction: Ca + 1/2 O2 → CaO. ..................(1)
In terms of oxidation and reduction, the reaction can be shown at
Oxidation: Ca → Ca2+ + 2e- .................(2)
Reduction: 1/2O2 + 2e- → O2-...................(3)
From, reaction 1 it can be seen that 1 mol of Ca reacts with 1/2 mol of O2 to form 1 mol of CaO.
From, reaction 2 it can be seen that 1 mol of Ca, generates 2 mol of e-.
Thus, when 1/2 mol of Ca is used in reaction, it will lose 1 mol of electrons.