This is weird.
All three 'choices' are true.
Line um up. (a) shows how to solve the problem. (b) does it. and (c) is the answer.
Let's call Q the initial charge of the object, which is:
![Q=-4](https://tex.z-dn.net/?f=Q%3D-4)
When it breaks, the two pieces will have charge
![Q_1](https://tex.z-dn.net/?f=Q_1)
and
![Q_2](https://tex.z-dn.net/?f=Q_2)
, and since the total charge must be conserved, the sum of these two charges must be equal to the initial charge of the object:
![Q=Q_1+Q_2](https://tex.z-dn.net/?f=Q%3DQ_1%2BQ_2)
We also know the charge of one of the two pieces:
![Q_1=-5](https://tex.z-dn.net/?f=Q_1%3D-5)
So, by substituting Q and Q1 into the equation, we can find the charge of the second piece, Q2:
Moon eclipse is when the moon interposes between the sun and behind the Earth. The moon passes behind the Earth into its umbra and not viceversa! This is possible when the three of them are ALIGNED (in syzygy). In Romania, there was such eclipse that could be seen at an October night last year.
Explanation:
Given that,
Wavelength of the laser light, ![\lambda=1062\ nm=1062\times 10^{-9}\ m](https://tex.z-dn.net/?f=%5Clambda%3D1062%5C%20nm%3D1062%5Ctimes%2010%5E%7B-9%7D%5C%20m)
The laser pulse lasts for, ![t=34\ ps=34\times 10^{-12}\ s](https://tex.z-dn.net/?f=t%3D34%5C%20ps%3D34%5Ctimes%2010%5E%7B-12%7D%5C%20s)
(a) Let d is the distance covered by laser in the given by, ![d=c\times t](https://tex.z-dn.net/?f=d%3Dc%5Ctimes%20t)
![d=3\times 10^8\times 34\times 10^{-12}](https://tex.z-dn.net/?f=d%3D3%5Ctimes%2010%5E8%5Ctimes%2034%5Ctimes%2010%5E%7B-12%7D)
d = 0.0102 meters
Let n is the number of wavelengths found within the laser pulse. So,
![n=\dfrac{d}{\lambda}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7Bd%7D%7B%5Clambda%7D)
n = 9604.51
(b) Let t is the time need to be fit only in one wavelength. So,
![t=\dfrac{\lambda}{c}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B%5Clambda%7D%7Bc%7D)
![t=\dfrac{1062\times 10^{-9}}{3\times 10^8}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B1062%5Ctimes%2010%5E%7B-9%7D%7D%7B3%5Ctimes%2010%5E8%7D)
![t=3.54\times 10^{-15}\ s](https://tex.z-dn.net/?f=t%3D3.54%5Ctimes%2010%5E%7B-15%7D%5C%20s)
Hence, this is the required solution.
Answer:
D
Explanation:
The rubber rod having been rubbed with fur get a net negative charge thereby gaining more mass which means the mass has increased compared to before it was rubbed against the fur while the glass rod having been rubbed with the silk to give it a net positive has lost mass and therefore has less mass compared to before it was rubbed on the silk.