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Reil [10]
3 years ago
9

What does expression equivalent mean?

Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0

Answer:


Step-by-step explanation:

Equivalent expressions are expressions that are the same,even though they might look different. If you plug in the same variable value into equivalent expressions they will each give you the same value when you simplify.

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Use Pythagorean theorem to find the missing length. (round to tenth if necessary) IS
sertanlavr [38]

11.7

Formula: a^2 + b^2 = c^2

so substitute the numbers like this:

10^2 + 6^2 = c^2

both 10^2 and 6^2 are perfect squares:

10 × 10= 100 and 6 × 6= 36

100 + 36= c^2

add:

100 + 36 =

136 = c^2

now in order to get rid of the squared, you put it into a radical:

√136 = √c^2

note: whatever you do on one side, you do to the other

it's easier to use the calculator for this so put √136 and you're gonna get 11.66

since it's asking you to round it to the nearest tenth:

11.66 = 11.7

sorry if the explanation is kinda long ✋ i tried explaining it better in the end but i failed

7 0
3 years ago
What is the value of angle e ?
konstantin123 [22]

Answer:

4 units pls mark me brainliest i really need it thanks

Step-by-step explanation:

7 0
3 years ago
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22. An employee joined a company in 2017 with a starting salary of $50,000. Every year this employee receives a raise of $1000 p
Setler79 [48]

Answer:

(a) The recurrence relation for the salary is

S_{n+1}=1.05*S_n+1000\\\\S_0=50000

(b) The salary 25 years after 2017 will be $217044.85.

(c) S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n

Step-by-step explanation:

We can define the next year salary S_{n+1} as

S_{n+1}=S_n+1000+0.05*S_n=1.05*S_n+1000

wit S0=$50000

If we extend this to 2 years from 2017 (n+2), we have

S_{n+2}=1.05*S_{n+1}+1000=1.05*(1.05*S_n+1000)+1000\\S_{n+2} =1.05^2*S_n+1.05*1000+1000\\S_{n+2}=1.05^2*S_n+1000*(1.05^1+1)

Extending to 3 years (n+3)

S_{n+3}=1.05*S_{n+2}+1000=1.05(1.05^2*S_n+1000*(1.05^1+1))+1000\\\\S_{n+3}=1.05^3S_n+1.05*1000*(1.05^1+1)+1000\\\\S_{n+3}=1.05^3*S_n+1000*(1.05^2+1.05^1+1)

Extending to 4 years (n+4)

S_{n+4}=1.05*S_{n+3}+1000=1.05*(1.05^3*S_n+1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1.05*1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1000*(1.05^3+1.05^2+1.05^1+1.05^0)

We can now express a general equation for S_n (salary at n years from 2017)

S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n

The salary at 25 years from 2017 (n=25) will be

S_{25}=1.05^{25}S_0+1000*\sum_{0}^{24}1.05^i\\\\S_{25}=3.386*50000+1000*47.72=217044.85

8 0
4 years ago
Can somebody help me ???
Ivahew [28]

Answer:

meth hArD3

Step-by-step explanation:

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3 years ago
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In the diagram shown, line "AB" is parallel to line "CD".<br><br>Find Z​ ​
erica [24]

Answer: z is 78

Step-by-step explanation:

5 0
3 years ago
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