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Rzqust [24]
3 years ago
6

Which letters represent constructive interference in this diffraction pattern? Check all that apply.

Physics
2 answers:
irakobra [83]3 years ago
7 0

Answer:A, C, and D id the correct answer

Explanation:

trasher [3.6K]3 years ago
4 0

Answer: A, C and D

Explanation:

Interference occurs when two waves superimpose to form a wave having a smaller or larger amplitude.

Constructive interference is said to occur when two waves superimpose to produce a wave having larger amplitude. It occurs for the waves having phase difference of multiple of 2π. On the other hand, destructive interference occurs for the waves having phase difference  π, 3π, ..and so on.

In the given picture, the bright regions represent constructive interference where as the dark ones between them represent destructive interference. Thus, the correct letters representing constructive interference are: A, C and D.

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What is the answer for this. please the correct answer only​
omeli [17]

Answer:

C. 900J (i tried my best)

Explanation:

the student's mass=60kg

gravitational field strength= 10N/kg:

1kg = 10N

60kg = 600N

(where 600N is the gravitational field strength of the student)

√1.5²+2² (pythagoras theorem)

=2.5m (the stairs' length)

work done= N x distance move in the direction of force (m)

=600N x 2.5m

=1500J @ Nm

1500J - 600N (gravitational field strength of the student)

=900J(??)

-correct me if i'm wrong i'm just a human :)

5 0
3 years ago
What is the resultant of a pair of one pound forces at right angles to each other?
OleMash [197]

Answer:

F_R=\sqrt{2} \ pound.force

Explanation:

Given that there are two force of 1 pound each at right angles to each other.

The from the vector law of addition:

F_R=\sqrt{F_1^2+F_2^2}

where:

F_R= resultant force

F_1\ \&\ F_2 be the two of the forces to be added.

F_R=\sqrt{1^2+1^2}

F_R=\sqrt{2} \ pound.force

8 0
4 years ago
7 2. Name the independent variable: 3. Name the dependent variable:​
charle [14.2K]

Answer:

independent variable is found on the x axis while dependent variable is found on the y axis

5 0
2 years ago
If you punched thousands of holes in the aluminum foil of the scope (so there were more "holes" than "foil"), how many imageswou
klasskru [66]

Answer:

If you punched thousands of holes in the aluminum foil, you would see thousands of small images in the viewer.

Explanation:

If thousands of holes is punched/perforated in an aluminum foil, such that there were more holes than foil.

Thousands of small images would be formed, which can be seen in the viewer. Aluminum foil has a good reflective property which allows the thousands of holes punched to reflect equal number of images, although the images are smaller in size than the original image size.

3 0
3 years ago
The trajectory of a rock ejected from the Kilauea volcano, with a velocity of magnitude 6.4 m/s and at angle 2.2 degrees above t
Vika [28.1K]

Answer:

v = 8.03 m / s

Explanation:

This is a missile throwing exercise.

          y = y₀ + v_{oy}  t - ½ g t²

     

indicates that y = -1.2 m and the initial velocity is

         v_{oy} = v₀ sin θ

         v_{oy} = 6.4 sin 2.2

         v_{oy} = 0.2457 m / s

we substitute in the equation

         -1.2 = 0.2457 t - ½ 9.8 t²

          4.9 t² - 0.2457 t - 1.2 = 0

          t² - 0.05014 t -0.2449 = 0

we solve the quadratic equation

          t = [0.05014 ±√ (0.05014² + 4 0.2449)] / 2

          t = [0.05014 ± 0.9910] / 2

          t₁ = 0.5206 s

          t₂ = -0.47 s

time must be a positive magnitude therefore the correct answer is

          t = 0.5206 s

with this time we can calculate the vertical speed when the rock hits the ground

         v_{y} = v_{oy} - gt

         v_{y} = 0.2457 - 9.8 0.5206

         v_{y} = -4.856 m / s

the negative sign indicates that the speed is down

horizontal velocity is constant, due to no acceleration

         vₓ = v₀ₓ = v₀ cos 2,2

         v₀ₓ = 6.4 cos 2.2

         v₀ₓ = 6.395 m / s

therefore let's use Pythagoras' theorem to find the velocity

         v = √ (vₓ² + v_{y}^{2})

         v = √ (6,395² + 4,856²)

         v = 8.03 m / s

the direction can be found with trigonometry

        tan θ = v_{y} / vₓ

        θ = tan⁻¹ (-4,856 / 6,395)

        θ = - 37

the negative sign indicates that it is half clockwise from the x axis

   

4 0
3 years ago
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