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kodGreya [7K]
3 years ago
7

A mixture is -

Chemistry
2 answers:
Fiesta28 [93]3 years ago
8 0

Answer:

C

Explanation:

an impure substance made through chemical process

nikitadnepr [17]3 years ago
6 0

Answer:

c is correct answer is I love this

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You are required to prepare 500 ml of a 6.00 M solution of HNO3 from a stock solution of 12.0 M. Describe in detail how you woul
andriy [413]

Answer: 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = concentration of stock solution = 12.0 M

V_1 = volume of stock solution = ?

C_2 = concentration of diluted solution= 6.00 M

V_2 = volume of diluted acid solution = 500 ml

Putting in the values we get:

12.0\times V_1=6.00\times 500

V_1=250ml

Thus 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

8 0
3 years ago
What devices will you use to measure the mass and the volume in this experiment? (density)
bekas [8.4K]

Answer:

Methods for determining or delivering precise volumes include volumetric pipets and pycnometers; less precise methods include burets, graduated cylinders, and graduated pipets. In this experiment, you will measure masses and volumes to determine density. Four different metal cylinders are investigated.

Explanation:

8 0
2 years ago
V.T2 = V2T, is an expression of
VashaNatasha [74]

Answer:

It corresponds to Charles' Law

Explanation:

Charles's Law corresponds to one of the gas laws, where temperature and volume are related, to constant pressure. That is, according to said equation, the volume of a gas varies directly with the temperature, under conditions of constant pressure.

3 0
3 years ago
What product(s) are formed during the complete combustion reaction that occurs when methane (CH4) and molecular oxygen (O2) reac
Vilka [71]

Answer: CO2 and H2O

Explanation: I already took the test it's right

3 0
3 years ago
What did Ernest Rutherford s gold foil experiment demonstrate about atoms?
mote1985 [20]
Rutherford performed gold foil experiment to understand that how negative and positive particles could Co exist in an atom. He bombarded alpha particles on a 0.00004 cm thick gold foil.

He proposed a planetary model of the atom and concluded following results and demonstrated that,
1. An atom produces a line spectrum.
2. An Electron revolves around the nucleus without any orbits.
3. Since most of the particles passed through the foil undeflected it means that most of the volume occupied by an atom is empty.
4. An Atom as a whole is neutral.
5. The deflection of few particles on the foil suggested that there is center of positive particles in an atom called the nucleus of the atom.
6. The complete rebounce of few particles on the gold foil suggested that the nucleus is very dense and hard.
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3 years ago
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