molar mass = (22.99) + (1.01) + (12.01) + 3(16.00)
molar mass = 84.01 g/mol
//
(508g)(1 mol/84.01 g) = 6.0
There are 6.0 moles of sodium bicarbonate
The atoms of hydrogen that are present in 7.63 g of ammonia(NH3)
find the moles of NH3 =mass/molar mass
7.63 g/ 17 g/mol = 0.449 moles
since there is 3 atoms of H in NH3 the moles of H = 0.449 x 3 = 1.347 moles
by use of 1 mole = 6.02 x10^23 atoms
what about 1.347 moles
= 1.347 moles/1 moles x 6.02 x10^23 atoms = 8.11 x10^23 atoms of Hydrogen
<u>Answer:</u> The molar solubility of 
is 
<u>Explanation:</u>
Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The balanced equilibrium reaction for the ionization of calcium fluoride follows:
s 2s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Pb^{2+}][I^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BI%5E-%5D%5E2)
We are given:
Putting values in above equation, we get:
Hence, the molar solubility of is
N = PV = (190 atm)(35 L) = 260 moles of gas RT (0.0821 L.atm/mol.K)(315 K)
Consider you have a mixture of amino acids(contains all set of amino acids such as polar, non polar). Other than TLC, how are you supposed to separate a single amino acid from the mixture without loss of amino acid quantitatively.
