You can use M x V = M' x V'
3 x V = 250 x 1.2
V = 100 ml
Answer:
C - no antibodies
Explanation:
I dont think there is any blood type without antibodies
Answer: 4
Explanation:
4 is the only one that has to products as well as having the plus at the bottom
Answer:
Head loss in turbulent flow is varying as square of velocity.
Explanation:
As we know that head loss in turbulent flow given as

Where
F is the friction factor.
L is the length of pipe
V is the flow velocity
D is the diameter of pipe.
So from above equation we can say that

It means that head loss in turbulent flow is varying as square of velocity.
We know that loss in flow are of two types
1.Major loss :Due to surface property of pipe
2.Minor loss :Due to change in momentum of fluid.
Answer:

Explanation:
Hola!
En este caso, consideramos que la disociación de ácido acético ocurre:

Así, mediante la solución del equilibrio ácido, podemos calcular la concentración de iones hidronio que posteriormente sirven para calcular el pH de la solución, por tal razón, debemos calcular el equilibrio dada la constante de equilibrio y por medio de la ley de acción de masas en términos del cambio
como cualquier problema de equilibrio:
![Ke=\frac{CH_3COO^-][H^+]}{[CH_3COOH]}\\\\1.76x10^{-5}=\frac{x*x}{1x10^{-14}M-x}](https://tex.z-dn.net/?f=Ke%3D%5Cfrac%7BCH_3COO%5E-%5D%5BH%5E%2B%5D%7D%7B%5BCH_3COOH%5D%7D%5C%5C%5C%5C1.76x10%5E%7B-5%7D%3D%5Cfrac%7Bx%2Ax%7D%7B1x10%5E%7B-14%7DM-x%7D)
Resolviendo para
, tenemos 
Así, la concentración de hidrógeno es igual a x, por lo que el pH:
![pH=-log([H^+])=-log(0.999x10^{-14})\\\\pH=14](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29%3D-log%280.999x10%5E%7B-14%7D%29%5C%5C%5C%5CpH%3D14)
Dicho valor tiene sentido desde que la concentración de hidrógeno es casi despreciable, por lo que se puede asumir que tiende a ser básica.
Saludos!