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exis [7]
3 years ago
13

If a certain mass has its velocity changed from 6.00 m/s to 7.50 m/s when a 3.00 n force acts for 4.00 seconds, find the mass of

the moving object.
Physics
2 answers:
Alika [10]3 years ago
6 0
<span>We know the relation between force and mass and acceleration follows this relation: F = m * a
   And we can calculate the acceleration as:
 Vf = Vi + a * t
  where Vf is final speed, Vi is initial speed, a is acceleration and t is time
 7.5 = 6 + a * 4
 7.5 - 6 = a * 4
 1.5 / 4 = a
 a= 0.375 m2/s
   The the mass is F = m * a 3 = m * 0.375 m = 8
   Then the mass is 8 kg</span>
shutvik [7]3 years ago
3 0
By definition we have that the force for time is equal to the product of the mass for the change in speed.
 We have then that
 F * (delta t) = m * (delta v)
 Clearing the mass
 m = (F * (delta t)) / (delta v)
 Substituting the values
 m = ((3.00) * (4.00)) / (7.50-6.00) = 8
 answer
 The mass of the moving object is 8Kg
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3 years ago
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Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

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From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

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6 0
1 year ago
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Refer to more about the potential difference here

brainly.com/question/12198573

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6 0
1 year ago
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