Answer:
the direction is towards upward.i think.
The answer is 18000 J
I hope this helps!^^ , if you need the work to be shown please tell me, I hope you have a great day!^^
The concept needed to solve this problem is average power dissipated by a wave on a string. This expression ca be defined as
Here,
= Linear mass density of the string
Angular frequency of the wave on the string
A = Amplitude of the wave
v = Speed of the wave
At the same time each of this terms have its own definition, i.e,
Here T is the Period
For the linear mass density we have that
And the angular frequency can be written as
Replacing this terms and the first equation we have that
PART A ) Replacing our values here we have that
PART B) The new amplitude A' that is half ot the wavelength of the wave is
Replacing at the equation of power we have that
Answer:
The minimum speed must the car must be 13.13 m/s.
Explanation:
The radius of the loop is 17.6 m. We need to find the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top.
We know that, mg be the weight of car and rider, which is equal to the centripetal force.
So, the minimum speed must the car must be 13.13 m/s.