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Feliz [49]
3 years ago
7

In the same condition, what happens to the net force acting on the rope?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

Explained below

Explanation:

Newton's law of inertia states that An object at rest will remain continue at rest or if in motion, will continue in motion unless in both cases it is acted upon by a net external force.

Now, If two forces on the rope are equal and opposite forces, then the net force on the rope will be zero and it will not move. Thus,balance force is present in the rope and the rope will remain at rest since the net force is zero or it will continue in motion if already in motion without stopping since net force is zero

However, if the forces are acting in the same direction, it will result in an unbalanced force which means that the net force will be equal to the sum of the two forces and this will result in a stronger force than even the 2 individual forces and consequently it will cause the rope at rest to move, or if the rope is in motion, it will cause it to stop.

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Order the atoms from largest to smallest: Cs , Si , Sn .
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Answer:

Si, Sn, Cs

Explanation:

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Silicon Si_______14___________0.117
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According to the following position vs. Time graph the bicyclist was
julia-pushkina [17]

Answer:

According to the following position vs. Time graph the bicyclist was : D

D. Not moving for the first two seconds, then begin moving at the constant speed.​

Explanation:

Speed = \frac{Distance}{time}

Along Y-axis = Distance in meters

Along X-axis = Time taken in second

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4 years ago
How many ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH
olganol [36]

Answer: 127.5ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.75M\\V_2=85mL

Putting values in above equation, we get:

1\times 0.5\times V_1=1\times 0.75\times 85\\\\V_1=127.5mL

Thus 127.5 ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

6 0
3 years ago
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