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Feliz [49]
3 years ago
7

In the same condition, what happens to the net force acting on the rope?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

Explained below

Explanation:

Newton's law of inertia states that An object at rest will remain continue at rest or if in motion, will continue in motion unless in both cases it is acted upon by a net external force.

Now, If two forces on the rope are equal and opposite forces, then the net force on the rope will be zero and it will not move. Thus,balance force is present in the rope and the rope will remain at rest since the net force is zero or it will continue in motion if already in motion without stopping since net force is zero

However, if the forces are acting in the same direction, it will result in an unbalanced force which means that the net force will be equal to the sum of the two forces and this will result in a stronger force than even the 2 individual forces and consequently it will cause the rope at rest to move, or if the rope is in motion, it will cause it to stop.

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A 0.5 mol sample of N2 is in a 6L container at 2 atm. what is the temperature of the gas in K
Andreas93 [3]

Answer:

300 K

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Diatomic Elements
  • Moles

<u>Gas Laws</u>

Ideal Gas Law: PV = nRT

  • <em>P</em> is pressure
  • <em>V</em> is volume
  • <em>n</em> is moles
  • <em>R</em> is gas constant
  • <em>T</em> is temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>n</em> = 0.5 mol N₂

[Given] <em>V</em> = 6 L

[Given] <em>P</em> = 2 atm

[Given] <em>R</em> = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] <em>T</em>

<em />

<u>Step 2: Solve for </u><em><u>T</u></em>

  1. Substitute in variables [Ideal Gas Law]:                                                          (2 atm)(6 L) = (0.5 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)T
  2. Multiply [Cancel out units]:                                                                               12 atm · L = (0.04105 L · atm · K⁻¹)T
  3. Isolate <em>T</em> [Cancel out units]:                                                                             292.326 K = T
  4. Rewrite:                                                                                                             T = 292.326 K

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig as our lowest.</em>

292.326 K ≈ 300 K

8 0
3 years ago
An unknown sample weighing 0.3512g was added to 20.0 mL of cyclohexane. The density of cyclohexane is 0.779g/mL, and the freezin
rjkz [21]

Explanation:

It is known that density is mass of a substance divided by its volume.

Mathematically,         Density = \frac{mass}{volume}

Therefore, calculate the mass of cyclohexane as follows.

             mass of cyclohexane = Density × volume

                                  = 0.779 g/mL \times 20 mL

                                   = 15.58 g

or,                              = 0.01558 kg           (as 1 kg = 1000 g)

As, K_{f} of cyclohexane = 20^{o}C/m  

                 \Delta T_{f} = K_{f} \times molality

                           5.2 = 20 \times molality

                             molality = \frac{5.2}{20}

                                         = 0.26 m

Also, molality is the number of moles of solute present in kg of solvent.

Mathematically,      molality = \frac{\text{no. of moles}}{\text{mass of solvent}}

                         0.26 = \frac{\text{no. of moles}}{0.01558}

                       No. of moles  = 4.05 \times 10^{-3}

As,             No. of moles = \frac{mass}{\frac{molar mass}}      

                    4.05 \times 10^{-3} = \frac{0.3512}{\text{molar mass}}

                             molar mass = 87.0 g/mol

Thus, we can conclude that molar mass of unknown substance is 87.0 g/mole.

4 0
3 years ago
I have a 5 liter container of oxygen (O 2 ) gas at 2.0 atm and 25 0 C, what mass of gas is inside this
Thepotemich [5.8K]

Answer:

m=13.1gO_2

Explanation:

Hello,

In this case, by using the ideal gas equation, we first compute the moles of oxygen at the given volume, pressure and temperature:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{2.0atm*5L}{0.082\frac{atm*L}{mol*K}(25+273.15)K}  =0.41mol

Then, since molar mass of gaseous oxygen is 32 g/mol, we compute the contained mass in grams as shown below:

m=0.41mol*\frac{32g}{1mol}\\\\m=13.1gO_2

Best regards.

3 0
4 years ago
PbO2 + 4HCl --- PbCl2 + Cl2 + 2H2O who buys electrons and who loses electrons?​
SIZIF [17.4K]

<u>Answer:</u> Electrons are taken up by PbO_2 and they are lost by HCl

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is also called the reaction where the exchange of electrons takes place.

An oxidation reaction is defined as the reaction in which a chemical species loses electrons takes place. In this reaction, the oxidation state of a substance gets increased.

A reduction reaction is defined as the reaction in which a chemical species gains electrons takes place. In this reaction, the oxidation state of a substance gets reduced.

For the given chemical reaction:

PbO_2+4HCl\rightarrow PbCl_2+Cl_2+2H_2O

The half-reactions for this redox rection follows:

<u>Oxidation half-reaction:</u>  2HCl\rightarrow ClO_2 + 2e^-

<u>Reduction half-reaction:</u>  PbO_2+2e^-\rightarrow PbCl_2

Hence, electrons are taken up by PbO_2 and they are lost by HCl

8 0
3 years ago
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BlackZzzverrR [31]
The app socratic will help you to get the answer
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3 years ago
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