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Feliz [49]
3 years ago
7

In the same condition, what happens to the net force acting on the rope?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

Explained below

Explanation:

Newton's law of inertia states that An object at rest will remain continue at rest or if in motion, will continue in motion unless in both cases it is acted upon by a net external force.

Now, If two forces on the rope are equal and opposite forces, then the net force on the rope will be zero and it will not move. Thus,balance force is present in the rope and the rope will remain at rest since the net force is zero or it will continue in motion if already in motion without stopping since net force is zero

However, if the forces are acting in the same direction, it will result in an unbalanced force which means that the net force will be equal to the sum of the two forces and this will result in a stronger force than even the 2 individual forces and consequently it will cause the rope at rest to move, or if the rope is in motion, it will cause it to stop.

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Give the names and symbols of three<br> elements that are gases at room temperature.
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Explanation:

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What is 30g(1mol÷70g)
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what is the boiling point of water at the top of mount everest where the atmospheric pressure is only 34% as strong
Tema [17]

This question is incomplete, the complete is;

Water has a heat of vaporization (ΔHvap) of 44.01 kJ mol-1 and boils at 100 degrees C at sea level.

What is the boiling point of water  at the top of Mount Everest where the atmospheric pressure is only 34% as strong as the pressure at sea level?

Answer: the boiling point of water at the top of mount Everest where the atmospheric pressure is only 34% as strong is 74 °C

Explanation:

Given that;

P1 = 1 atm,

T1 = 100°C =  373 K

P2 = P1 × 34% = 1×0.34 = 0.34 atm

T1 = ?

ΔH = 44.01 kJ mol⁻¹ = 44.01×10³ J/mol

R = 8.314 J/k.mol

now using the Clausius - Clapeyron equation;

p1_∫^p2 d.InP = ΔHvap/R T1_∫^T2. 1/T².dT

⇒ In(P2/P1) = ΔHvap/R (1/T1 - 1/T2)

so we substitute;

ln( 0.34/1 ) = ( 44.01×10³ / 8.314) × ( 1/373 - 1/T2)  

-1.0788 = 5293.4808 × ( 0.00268 - 1/T2)

-1.0788 = 14.1865 - 5293.4808(1/T2)

5293.4808(1/T2) = 14.1865 + 1.0788

5293.4808(1/T2) = 15.2653

(1/T2) = 15.2653 / 5293.4808

(1/T2) = 0.0028837

T2 = 1 / 0.0028837

T2 = 346.8 K

WE convert to Celsius

t2 =346.8 K − 273.15 = 73.65 °C ≈ 74 °C

Therefore, the boiling point of water at the top of mount Everest where the atmospheric pressure is only 34% as strong is 74 °C

8 0
3 years ago
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