Answer:
MM = 680g / mol
Explanation:
Hello! To calculate the molar mass of the compound (g / mol), I first have to calculate the molarity.
Molarity can be calculated from the osmotic pressure equation.
op = M * R * T
op = osmotic pressure = 28.1mmHg * (1 atm / 760mmHg) = 0.037atm
M = molarity
R = gas constant
T = temperature (K) = 20 ° C + 273.15 = 293.15K
M (mol / L) = op / R * T
M = 0.037atm / ((0.082 (atm * L) / (K * mol)) * 293.15K) = 0.0015mol / L
As I have the volume = 100ml * (1L / 1000ml) = 0.1L
I can calculate the amount of moles
n = M * V = 0.0015 * 0.1 = 0.00015mol
n = m / MM
m = mass
MM = molar mass
MM = m / n = 0.102g / 0.00015mol
MM = 680g / mol
Answer:
The rate of acceleration is 5.
Explanation:
In order to calculate acceleration we need to divide the force by the mass.
Acceleration = net force/mass
In this case, it would be 20/4. Simplify that and we get 5.
Hydrogen and oxygen are different elements.
when two or more elements combine, they form a compound
hence, two molecules of hydrogen and one molecule of oxygen combine to form water as a compound
Answer: The answer is Parasite ma dude
Explanation:
In evolutionary ecology, parasitism is a symbiotic relationship between species, where one organism, the parasite, lives on or in another organism, the host, causing it some harm, and is adapted structurally to this way of life.
Hopes this helps
Answer:
The final concentration is 0.226 M.
Explanation:
In this problem the dilution has occurred two times. So the symbol initial concentration, concentration after first dilution and the concentration after second dilution is given as C1, C2, and C3 respectively. Same can be done for the volume i.e, V1, V2, and V3 will be the initial volume, the volume taken after first dilution, and the volume after second dilution.
So, let's use the dilution formula for the first dilution
![C_1 \times V_1 = C_2 \times V_2](https://tex.z-dn.net/?f=C_1%20%5Ctimes%20V_1%20%3D%20C_2%20%5Ctimes%20V_2)
![C_2 = \frac{C_1\times V_1}{V_2}\\\\C_2 = \frac{1.50\times 51.0}{208}\\\\C_2 = 0.368 M](https://tex.z-dn.net/?f=C_2%20%3D%20%5Cfrac%7BC_1%5Ctimes%20V_1%7D%7BV_2%7D%5C%5C%5C%5CC_2%20%3D%20%5Cfrac%7B1.50%5Ctimes%2051.0%7D%7B208%7D%5C%5C%5C%5CC_2%20%3D%200.368%20M)
Now, for the second dilution
![C_2 \times V_2 = C_3 \times V_3\\\\C_3 = \frac {C_2 \times V_2}{V_3}\\\\C_3 = \frac {0.368 \times 104}{169}\\\\C_3 = 0.226 M](https://tex.z-dn.net/?f=C_2%20%5Ctimes%20V_2%20%3D%20C_3%20%5Ctimes%20V_3%5C%5C%5C%5CC_3%20%3D%20%5Cfrac%20%7BC_2%20%5Ctimes%20V_2%7D%7BV_3%7D%5C%5C%5C%5CC_3%20%3D%20%5Cfrac%20%7B0.368%20%5Ctimes%20104%7D%7B169%7D%5C%5C%5C%5CC_3%20%3D%200.226%20M)