Answer:
The intensity of sound at rock concert is 10¹⁰ greater than that of a whisper.
Explanation:
The intensity of sound is given by;

where;
I is the intensity of the sound
I₀ is the threshold of sound intensity = 1 x 10⁻¹² W/m²
The intensity of sound at a rock concert

The intensity of sound of a whisper

Thus, the intensity of sound at rock concert is 10¹⁰ greater than that of a whisper.
Answer
The ways are;
• By commercializing low earth orbit
• By supporting water purification efforts worldwide
• By bringing space station ultrasound equipment on earth
• By improving eye surgery with space hardware
Explanation
There is a revolutionary commercial pathways that is currently opening access to space.For example, NASA is purchasing commercial cargo resupply to space station which enable U.S business to develop a competition in selling services to others while freeing NASA resources for deep space exploration. Using technology developed in space, the Water Security Corporation has deployed systems using NASA water-processing technology to ensure drinkable water availability for human survival. Medical care in remote regions is now facilitated by use of small ultrasound units, tele-medicine and remote guided methods similar to those used in space. The Eye Tracking Device experiment has enable researchers to have an insight into corrective laser surgeries.
MgCl2 is ionic compound.........Mg +2 and Cl -1
both charges are cross multiplied to each element......formula tells us that to balance the positive and negative charges on both sides they are cross multiplied........MgCl2......meaning there is one atom of Mg and 2 atoms of Cl.......
HOPE IT HELPS !!!
B - A theory seems to be the closest
Answer:

between the plates.
Explanation:
The equation for change of voltage between two points separated a distance d inside parallel conducting plates (<em>which have between them constant electric field</em>) is:

So to calculate our electric field strength we use the fact that the potential 8.8 cm from the zero volt plate is 475 V:

And we use the fact that the plates are 9.2cm apart to calculate the voltage between them:
