The wavelength of the note is

. Since the speed of the wave is the speed of sound,

, the frequency of the note is

Then, we know that the frequency of a vibrating string is related to the tension T of the string and its length L by

where

is the linear mass density of our string.
Using the value of the tension, T=160 N, and the frequency we just found, we can calculate the length of the string, L:
Let R be radius of Earth with the amount of 6378 km h = height of satellite above Earth m = mass of satellite v = tangential velocity of satellite
Since gravitational force varies contrariwise with the square of the distance of separation, the value of g at altitude h will be 9.8*{[R/(R+h)]^2} = g'
So now gravity acceleration is g' and gravity is balanced by centripetal force mv^2/(R+h):
m*v^2/(R+h) = m*g' v = sqrt[g'*(R + h)]
Satellite A: h = 542 km so R+h = 6738 km = 6.920 e6 m g' = 9.8*(6378/6920)^2 = 8.32 m/sec^2 so v = sqrt(8.32*6.920e6) = 7587.79 m/s = 7.59 km/sec
Satellite B: h = 838 km so R+h = 7216 km = 7.216 e6 m g' = 9.8*(6378/7216)^2 = 8.66 m/sec^2 so v = sqrt(8.32*7.216e6) = 7748.36 m/s = 7.79 km/sec
Answer:
Explanation:
It can be increased by: increasing the rate of rotation. Increasing the strength of the magnetic field. Increasing the number of turns on the coil.
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Lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students. Option D is correct.
<h3>
What is a Transverse wave?</h3>
- The wave in which the oscillation of particles is is perpendicular to the direction of energy transfer.
- The students can make a transverse wave by raising their hands up and then down, one student at a time.
- The raised hand represents the oscillation of particles while the sequence of the raising hand represents the direction of energy transfer.
Therefore, lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students.
Learn more about Transverse waves:
brainly.com/question/3813804
Answer:
Explanation:
You can calculate the total electric charge that passes through the conductor as
. It means that the number of electron that passes through the conductor is: