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kow [346]
3 years ago
8

Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 1.50μm2. Conve

rt this to square meters.
Chemistry
1 answer:
Serhud [2]3 years ago
3 0
.0000015 meters squared. just got to move the decimal


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lyudmila [28]
Cells correct error in their DNA by three processes: proofreading (errors that occur during replication are rectified), mismatch repair (the mismatched base pairs are corrected just after the DNA replication), and damage repair mechanisms (including direct reversal by cell enzymes, excision repair by replacement or removal of the wrong base, and double stranded base repair by repairing the breaks in the DNA by homologous or non-homologous recombination methods). Pick according to this answer >)
3 0
4 years ago
I have no idea how to do this, any help would be appreciated
aksik [14]
Proton number = the atomic number (which is the smaller number
neutron number = the mass number (the bigger number) - the atomic number
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i would solve the whole thing but its unclear hope this helps tho
6 0
3 years ago
When working with chemicals, a good practice to read about any safety ____ or actions that are taken to prevent harm
madreJ [45]

Answer:

Precautions

Explanation:(Grammar Check)

4 0
4 years ago
At what time will the pressure of SO₂Cl₂ decline to 0.50 its initial value? Express your answer using two significant figures.
QveST [7]

Answer: The time is 0.69/k seconds

Explanation:

The following integrated first order rate law

ln[SO₂Cl₂] - ln[SO₂Cl₂]₀ = - k×t

where

[SO₂Cl₂] concentration at time t,

[SO₂Cl₂]₀ initial concentration,

k rate constant

Therefore, the time elapsed after a certain concentration variation is given by:

t=\frac{ln[SO_{2}Cl_{2}]_{0} - ln[SO_{2}Cl_{2}]}{k}=\frac{ln\frac{[SO_{2}Cl_{2}]_{0}}{[SO_{2}Cl_{2}]} }{k}

We could assume that SO₂Cl₂ behaves as a ideal gas mixture so partial pressure is proportional to concentration:

p_{(SO_{2}Cl_{2})}V = n_{(SO_{2}Cl_{2})}RT

[SO_{2}Cl_{2}]= \frac{n_{(SO_{2}Cl_{2})}}{V}}=\frac{p_{(SO_{2}Cl_{2})}}{RT}}

In conclusion,

t = ln( p(SO₂Cl₂)₀/p(SO₂Cl₂) )/k

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{p_{(SO_{2}Cl_{2})}} }{k}

for

p_{(SO_{2}Cl_{2})}=0.5p_{(SO_{2}Cl_{2})}_{0}

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{0.5p_{(SO_{2}Cl_{2})_{0}}} }{k}

t=\frac{ln\frac{1}{0.5} }{k}

t=\frac{ln(2)}{k}

t=\frac{0.69}{k}}

7 0
3 years ago
4. Some characteristic types of wind result where global pressure belts meet. Which of the following is a zone of weak, variable
PIT_PIT [208]

Answer:

local winds

Explanation:

4 0
3 years ago
Read 2 more answers
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