Answer:
14 g of N2
Explanation:
If we look at the options, we will notice that the correct answer needs to be a gas that has about half of the molecular mass of the gas.
If we consider nitrogen gas whose molecular mass is 28g/mol, half of the molecular mass is 14 g.
So;
28g of N2 contains 6.02 × 10^23 molecules of N2
14g of N2 contains 14 × 6.02 × 10^23 /28
= 3.0 x 10^23
At first quarter and last quarter, the Moon lies perpendicular to a line between Earth and the Sun. We see exactly half of the Moon illuminated by the Sun — the other half lies in shadow. Hope it helps :)
Explanation:
1) Based on the octet rule, iodine form an <u>I</u>⁻ ion.
Therefore,
Option E is correct ✔
2) The electronic configuration of the sulfide ion (S²⁻) is :
₁₆S = 1s² 2s² 2p⁶ 3s² 3p⁴ or [Ne] 3s² 3p⁴
₁₈S²⁻ = 1s² 2s² 2p⁶ 3s² 3p⁶ or [Ne] 3s² 3p⁶
Therefore,
Option E is correct ✔
3) valence shell electron of
Halogens = 7
Alkali metal = 1
Alkaline earth metal = 2
Therefore,
Option D is correct ✔
4) Group 2 element lose two electron in order to achieve Noble gas configuration.
And here Group 2 element is Sr
Therefore,
Option B is correct ✔
5) Group 13 element lose three electron in order to achieve Noble gas configuration.
And here Group 13 element is Al
Therefore,
Option B is correct ✔
6) For a given arrangements of ions, the lattice energy increases as ionic radius <u>decreases</u> and as ionic charge <u>increases</u>.
Therefore,
Option A is correct ✔
Answer:
244.7 g of acetylene
Explanation:
The balanced reaction equation is shown below;
2H20 (l) + CaC2 (s) → Ca(OH)2 (s) + C2H2 (g)
Number of moles of were reacted = reacting mass/molar mass = 358g/18gmol-1 = 19.89 moles of water
From the balanced reaction equation;
2 moles water yields 1 mole of acetylene
19.89 moles of water will yield 19.89 × 1/2 = 9.945 moles of acetylene
Theoretical yield of acetylene = 9.945 moles of acetylene × molar mass of acetylene
Molar mass of acetylene = 26.04 g/mol
Theoretical yield of acetylene = 9.945 moles of acetylene × 26.04 g/mol
Theoretical yield of acetylene = 258.9678 g of acetylene
% yield = actual yield/ theoretical yield × 100
94.5 = actual yield/258.9678 g × 100
Actual yield= 94.5 × 258.9678 g/100
Actual yield = 244.7 g of acetylene
