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3 years ago

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PLEASE ANSWER QUICK I WILL MARK BRAINLIEST A spreadsheet is a _____. A. way to organize data on a computer B. place to list obse

rvations and inferences C. tool that makes using a microscope easier D. part of your lab notebook used for writing vocabulary

1 answer:

Oxana [17]3 years ago

3 0

Answer:

The answer is D part of your lab notebook used for writing vocabulary

Hope it helps!

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Be sure to answer all parts. In the average adult male, the residual volume (RV) of the lungs, the volume of air remaining after

Alenkinab [10]

<u>Answer:</u>

<u>For a:</u> The number of moles of air present in the RV is 0.047 moles

<u>For b:</u> The number of molecules of gas is $2.83\times 10^{22}$

<u>Explanation:</u>

<u>For a:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

$PV=nRT$

where,

P = pressure of the air = 1.00 atm

V = Volume of the air = 1200 mL = 1.2 L (Conversion factor: 1 L = 1000 mL)

T = Temperature of the air = $37^oC=[37+273]K=310K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of air = ?

Putting values in above equation, we get:

$1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol$

Hence, the number of moles of air present in the RV is 0.047 moles

<u>For b:</u>

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, 0.047 moles of air will contain $(0.047\times 6.022\times 10^{23})=2.83\times 10^{22}$ number of gas molecules.

Hence, the number of molecules of gas is $2.83\times 10^{22}$

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2 years ago

A 1000-ml bag of d5w 1/2 ns is to infuse over 8 hours. what is the flow rate of the infusion?

AlladinOne [14]

1542 is the answer. : )

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3 years ago

30 mL of 0.6 M HCl solution is neutralized with 90 mL NaOH solution. What is the concentration of the base? Show all work Please

skad [1K]

From

<em>n</em><em>a</em><em>=</em><em>1</em>

<em>n</em><em>b</em><em>=</em><em>1</em>

<em>V</em><em>a</em><em>=</em><em>3</em><em>0</em><em>m</em><em>l</em><em>s</em>

<em>V</em><em>b</em><em>=</em><em>9</em><em>0</em><em>m</em><em>l</em><em>s</em>

<em>M</em><em>a</em><em>=</em><em>0</em><em>.</em><em>6</em><em>M</em>

<em>M</em><em>b</em><em>=</em><em>?</em>

<em>f</em><em>r</em><em>o</em><em>m</em>

<em>Mb</em><em>=</em><em><u>M</u></em><em><u>a</u></em><em><u>×</u></em><em><u>V</u></em><em><u>a</u></em><em><u>×</u></em><em><u>n</u></em><em><u>b</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>V</em><em>b</em><em>×</em><em>n</em><em>a</em>

<em>M</em><em>b</em><em>=</em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>×</u></em><em><u>3</u></em><em><u>0</u></em><em><u>×</u></em><em><u>1</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>9</em><em>0</em><em>×</em><em>1</em>

<em>m</em><em>b</em><em>=</em><em><u>1</u></em><em><u>8</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>9</em><em>0</em>

<em>M</em><em>b</em><em>=</em><em>0</em><em>.</em><em>2</em><em>M</em>

<em>NaOH</em><em>=</em><em>4</em><em>0</em>

<em>F</em><em>r</em><em>o</em><em>m</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>m</em><em>o</em><em>l</em><em>a</em><em>r</em><em>i</em><em>t</em><em>y</em><em>×</em><em>m</em><em>r</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>0</em><em>.</em><em>2</em><em>×</em><em>4</em><em>0</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>8</em><em>g</em><em>/</em><em>m</em><em>o</em><em>l</em>

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2 years ago

A box with a mass of 3.5 kg is pushed along a table. If the net force on the box is 35 Newtons, what is the acceleration of the

Vesnalui [34]

Answer:

<h2>10 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

m is the mass

f is the force

From the question

mass = 3.5 kg

force = 35 N

We have

$a = \frac{35}{3.5} \\ = 10$

We have the final answer as

<h3>10 m/s²</h3>

Hope this helps you

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Answer:

Leroy Jeakins

Explanation:

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