Which of the following situations would cause the greatest decrease in the motion of molecules in a system?

A geosynchronous satellite orbits Earth at a distance of 42,250 km from the center of Earth and has a period of 1 day. What is t

yan [13]

Answer:

The centripetal acceleration of the satellite is $a=0.22\ m/s^2$ .

Explanation:

Given that,

The distance covered by a geosynchronous satellite, d = 42250 km

The time taken by the satellite to covered distance, t = 1 day = 24 hours

Since, 24 hours = 86400 seconds

Let v is the speed of the satellite. It is given by the total distance divided by total time taken such that :

$v=\dfrac{d}{t}$

$v=\dfrac{2\pi d}{t}$

$v=\dfrac{2\pi\times 42250 \times 10^3}{86400 }$

v = 3072.5 m/s

The centripetal acceleration of the satellite is given by :

$a=\dfrac{v^2}{d}$

$a=\dfrac{(3072.5)^2}{42250 \times 10^3}$

$a=0.22\ m/s^2$

So, the centripetal acceleration of the satellite is $a=0.22\ m/s^2$ . Hence, this is the required solution.

7 0

3 years ago

17. A 120 m long train is moving in a direction with speed 20 m/s. A train B moving with 30

nydimaria [60]

Answer is D.

Speed:
Use relative speed to simplify the situation. Since the trains are moving in opposite directions, you can add the speeds and pretend the first train is stationary (moving at 0m/s) and the second train is moving at 50m/s.

Distance:
The front of the second train needs to travel 120m to get from the front to the back of the first train. When the front of the second train is at the back of the first train, the back of the second train is still 10m in front of the first train. The back therefore has to travel 130m to clear the first train. The total distance over which the trains are overlapping in this scenario is therefore 120 + 130 = 250m.

You have speed and you have distance so now just calculate time:

v = d / t
50 = 250 / t
t = 5s

4 0

3 years ago

A"boat"is"moving"to"the"right"at"5"m/s"with"respect"to"the"water."A"wave"moving"to"the"left,"opposite"the"motion"of"the"boat."Th

s2008m [1.1K]

Answer:

0.99m

Explanation:

Firs you calculate the relative velocity between the boat and the wave. The velocity of the boat is 5m/s and the velocity of the wave is given by:

$v=\lambda f=\lambda\frac{1}{T}=(110m)\frac{1}{8.3s}=13.25\frac{m}{s}$

the relative velocity is:

$v'=13.25m/s-5m/s=8.25\frac{m}{s}$

This velocity is used to know which is the distance traveled by the boat after 20 seconds:

$x'=v't=(8.25m/s)(20s)=165m$

Next, you use the general for of a wave:

$f(x,t)=Acos(kx-\omega t)=Acos(\frac{2\pi}{\lambda}x-\omega t)$

you take the amplitude as 2.0/2 = 1.0m.

$\omega=\frac{2\pi}{T}=\frac{2\pi}{8.3s}=0.75\frac{rad}{s}$

by replacing the values of the parameters in f(x,t) you obtain the vertical displacement of the boat:

$f(165,20)=1.0m\ cos(\frac{2\pi}{110m}(165)-(0.75\frac{rad}{s})(20s))\\\\f(165,20)=0.99m$

6 0

4 years ago

A large capacitor in an air conditioner is typically connected to the potential difference provided to your house (120 V). Altho

fomenos

Answer:

$A=7.72\times 10^{-18}\ m^2$

Explanation:

Given:

the voltage of the source, $V=120\ V$

distance of separation between the capacitor plates, $d=2\times 10^{-3}\ J$

energy of the capacitor, $U=0.25\ J$

Assuming that there is free space between the plates, so the permittivity, $\epsilon=9\times 10^{9}\ N.m^2.C^{-2}$

<u>We have the energy stored in a capacitor as:</u>

$U=\frac{1}{2}\times \frac{\epsilon.A.V^2}{d}$

$0.25=0.5\times \frac{9\times 10^{9}\times A\times 120^2}{2\times 10^{-3}}$

$A=7.72\times 10^{-18}\ m^2$

5 0

4 years ago

Read 2 more answers

The distance between Earth and Mars is 225 million km. When converted using the conversion factor 1 AU = 1.5 × 108 km, the dista

noname [10]

To convert km to AU, we divide 225,000,000 km by the factor of 1.5 x 10^8 = 150,000,000 km. This gives us 225,000,000 / 150,000,000 = 1.5 AU. Therefore, the distance between Earth and Mars in AU is 1.5 AU.
The AU is not equivalent to a light-year. A light-year is equivalent to around 9.5 x 10^12 kilometers.

4 0

4 years ago