Answer:
force = 11.33 
Explanation:
given data:
sled mass = 17.0 kg
inital velocity (U) = 4.10 m/s
elapsed time (T) 6.15 s
final velocity (V) = 0
final momentum P2 = 0
Initial momentum of sledge is
from newton second law of motion
Kgm/s^2
![F = \frac{69.7-0}{6.15}= 11.33[tex]kg-m/s^{2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B69.7-0%7D%7B6.15%7D%3D%2011.33%5Btex%5Dkg-m%2Fs%5E%7B2%7D)
[/tex]
Answer: 29.50 m
Explanation: In order to calculate the higher accelation to stop a train without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:
f=μ*N the friction force is equal to coefficient of static friction multiply the normal force (m*g).
f=m.a=μ*N= m*a= μ*m*g= m*a
then
a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2
With this value we can determine the short distance to stop the train
as follows:
x= vo*t- (a/2)* t^2
Vf=0= vo-a*t then t=vo/a
Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m
The weight of air resting on a surface, divided by the area
of the surface ... described in units of force per unit area ...
is called air pressure.
A should be the answer since it makes the water down there cold and the air also. (asked my grandma haha
