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rosijanka [135]
3 years ago
13

KATZPSEF1 30.P.041. My Notes Ask Your Teacher A charged particle enters a region of space with a uniform magnetic field B = 1.98

i T. At a particular instant in time, it has velocity v = (1.46 ✕ 106 i + 2.42 ✕ 106 j) m/s. Based on the observed acceleration, you determine that the force acting on the particle at this instant is F = 1.60 k N. What are the following?(a) the sign of the charged particle
(b) the magnitude of the charged particle

Physics
1 answer:
sladkih [1.3K]3 years ago
6 0

Answer: The charge on the particle is positive

While the magnitude = 0.00028C

Explanation:

Please find the attached file for the solution

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