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Answer:
(b) By including a statement that he or she is licensed by the Board for Professional Engineers and Land Surveyors immediately above the signature line in at least 12 point type on all contracts for services
Explanation:
A PE(professional engineer) licensee must show that he is licensed in order to show and ensure public safety as he is qualified for the job he is handling. The California regulations on professional engineers holds that all professional engineers must be licensed by the board of professional engineers and Land surveyors in order to operate legally as an engineer. The engineer may show licensure through the following options:
The engineer might provide statement to each client to show he is licensed which would then be signed by the client
The engineer may choose to post a wall certificate in his work premises to show he is licensed
The engineer may choose to include a statement of license in a letterhead or contract document which must be above the client's signature line and not less than 12 point type
Answer:
For the two you haven't answered: (Drag greater than thrust, lift greater than weight) It will accelerate backwards (decelerate) and upwards
(Lift greater than weight, thrust greater than drag) accelerate upwards and forwards.
Answer:
200
Explanation:
A size sheets (also known as letter size) are 8.5 inches by 11 inches.
B size sheets (also known as ledger size) are 11 inches by 17 inches.
One B size sheet is twice as large as a A size sheet. So if you have 100 B size sheets and cut each one in half, you'll get 200 A size sheets.
Answer:
62990.08 N/M
Explanation:
Circumferential stress, or hoop stress, a normal stress in the tangential (azimuth) direction. axial stress, a normal stress parallel to the axis of cylindrical symmetry. radial stress, a stress in directions coplanar with but perpendicular to the symmetry axis.
See attachment for the step by step solution of the given problem..
Answer:
a) 84.034°C
b) 92.56°C
c) ≈ 88 watts
Explanation:
Thickness of aluminum alloy fin = 12 mm
width = 10 mm
length = 50 mm
Ambient air temperature = 22°C
Temperature of aluminum alloy is maintained at 120°C
<u>a) Determine temperature at end of fin</u>
m = √ hp/Ka
= √( 140*2 ) / ( 12 * 10^-3 * 55 )
= √ 280 / 0.66 = 20.60
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