The pressure inside the can upon cooling is 0.4 atm.
<u>Explanation:</u>
Given -
Initial Temperature, T1 = 908°C = 908 + 273 K = 1181 K
Final Temperature, T2 = 208°C = 208 + 273 K = 481 K
Pressure upon cooling, P2 = ?
Using Gay Lussac's law:
P1/T1 = P2/T2
P2 = P1 X T2 / T1
P2 = 1 atm X 481 / 1181
P2 = 0.4 atm
Therefore, the pressure inside the can upon cooling is 0.4 atm.
Answer:
Following are the solution to this question:
Explanation:
The number of vacancies by the cubic meter is determined.




Answer:
Tm = 366.66k
Explanation:
check for the step by step explanation in the attachment
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Answer:
23.3808 kW
20.7088 kW
Explanation:
ρ = Density of oil = 800 kg/m³
P₁ = Initial Pressure = 0.6 bar
P₂ = Final Pressure = 1.4 bar
Q = Volumetric flow rate = 0.2 m³/s
A₁ = Area of inlet = 0.06 m²
A₂ = Area of outlet = 0.03 m²
Velocity through inlet = V₁ = Q/A₁ = 0.2/0.06 = 3.33 m/s
Velocity through outlet = V₂ = Q/A₂ = 0.2/0.03 = 6.67 m/s
Height between inlet and outlet = z₂ - z₁ = 3m
Temperature to remains constant and neglecting any heat transfer we use Bernoulli's equation

Work done by pump

∴ Power input to the pump 23.3808 kW
Now neglecting kinetic energy

Work done by pump

∴ Power input to the pump 20.7088 kW