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solniwko [45]
3 years ago
14

Jupiter orbits the sun once every 4333 days in a circle of radius 7.79 * 10^10 m. What is Jupiter’s velocity

Physics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

Velocity = 1306.76m/s

Explanation:

Given

r = 7.79 * 10^{10}m

Time = 4333 days

Required

Determine Jupiter's velocity

First, we calculate the circumference (C) of Jupiter:

C = 2\pi r

Substitute values for r and \pi

C = 2 * 3.14 * 7.79 * 10^{10}m

C = 489212000000m

Next, convert time to seconds:

Time = 4333 days

Time = 4333 * 60 * 60 * 24s

Time = 374371200s

The velocity is then calculated as:

Velocity = \frac{Circumference}{Time}

Velocity = \frac{489212000000m}{374371200s}

Velocity = 1306.76m/s

<em>Hence, Jupiter's velocity is 1306.76m/s</em>

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A piece of wood has a mass of 8g and a volume of 10cm³ work out the density of the wood
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<h2>0.8 g/cm³</h2>

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Air enters a nozzle steadily at 2.21 kg/m3 and 40 m/s and leaves at 0.752 kg/m3 and 180 m/s. If the inlet area of the nozzle is
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Answer

Given,

Air enter density, ρ₁ = 2.21 kg/m³

speed of entry, v₁ = 40 m/s

Air exit density , ρ₂ = 0.752 kg/m³

speed of exit, v₂ = 180 m/s

Inlet area = 90 cm²

a) mass flow rate through nozzle.

   m = \rho_1 A_1 v_1

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Exit area of nozzle is equal to 58\ cm^2

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