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solniwko [45]
2 years ago
14

Jupiter orbits the sun once every 4333 days in a circle of radius 7.79 * 10^10 m. What is Jupiter’s velocity

Physics
1 answer:
sashaice [31]2 years ago
7 0

Answer:

Velocity = 1306.76m/s

Explanation:

Given

r = 7.79 * 10^{10}m

Time = 4333 days

Required

Determine Jupiter's velocity

First, we calculate the circumference (C) of Jupiter:

C = 2\pi r

Substitute values for r and \pi

C = 2 * 3.14 * 7.79 * 10^{10}m

C = 489212000000m

Next, convert time to seconds:

Time = 4333 days

Time = 4333 * 60 * 60 * 24s

Time = 374371200s

The velocity is then calculated as:

Velocity = \frac{Circumference}{Time}

Velocity = \frac{489212000000m}{374371200s}

Velocity = 1306.76m/s

<em>Hence, Jupiter's velocity is 1306.76m/s</em>

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For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
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Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

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3 years ago
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Answer:

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3 years ago
In just 0.30 s , you compress a spring (spring constant 5000 n/m ), which is initially at its equilibrium length, by 4.0 cm. par
Ierofanga [76]
The average power output is the ratio between the work done to compress the spring, W, and the time taken, t:
P= \frac{W}{t} (1)

The work done is equal to the elastic energy stored by the compressed spring:
W=U= \frac{1}{2}kx^2
where k=5000 N/m is the spring constant and x=4.0 cm=0.04 m is the compression of the spring. If we substitute the numbers, we find:
W= \frac{1}{2}(5000 N/m)(0.04 m)^2=4 J

And now we can use eq.(1) to calculate the average power output:
P= \frac{W}{t}= \frac{4 J}{0.30 s}  =13.3 W
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3 years ago
Question :
irakobra [83]

A rubber ball and a stone of the same size are examples which will have more inertia and is therefore denoted as option A.

<h3>What is Inertia?</h3>

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The size of a rubber ball and stone will have different masses in which that of the stone will be greater. This is as a result of the difference in the nature of the substances which are used to make both items mentioned above.

This is therefore the reason why  a rubber ball and a stone of the same size as having more inertia(mass) where chosen as the most appropriate choice in this scenario.

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2 years ago
The SI unit of current is the ampere, which is defined as the flow of charge in units of _____ over a period of time measured in
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The SI unit of current is the ampere, which is defined as the flow of charge in units of <u>coulomb</u> over a period of time measured in <u>seconds.</u>

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<h3>What is Current?</h3>

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent the current. The ampere, denoted by the letter A, is the common unit. An ampere is a unit of measure of the rate of electron flow or current in an electrical conductor. One coulomb of electrical charge (6.24 x 1018 charge carriers) traveling by a given place in one second is represented by one ampere of current.

Conventional current, also known as Franklin current, is thought by physicists to flow from relatively positive points to comparatively negative locations. The most prevalent charge carriers, electrons, are negatively charged. From somewhat negative to relatively good points, they move.

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